Free Algebra 03 Practice Test - 6th grade
Question 1
Value of 2xy when x=4 and y=0 is _________.
0
8
16
6
SOLUTION
Solution : A
2xy=2× x× y
On substituting the values of x and y, we get2xy=2× 4× 0=8× 0=0
Question 2
A number when multiplied by 2 and decreased by 41 gives 3. Find the number.
18
20
22
24
SOLUTION
Solution : C
Let the number be x.
∴2x−41=3⇒2x=44⇒x=442=22
Question 3
The coefficient of term xy2 in expression 4xy2+x3−x5+2xy2 is ______.
SOLUTION
Solution : D
Since 4xy2 and 2xy2 are like terms, the given expression can be written as follows.
4xy2+x3−x5+2xy2=6xy2+x3−x5
Therefore, the coefficient of xy2 is 6.
Question 4
Which of the following is a variable?
SOLUTION
Solution : C
The temperature of a place in a day at different times will be different. So it is a variable.
The number of days in a week and the number of months in a year always remain the same. So these are constants.
5 has a fixed value. So it is a constant.
Question 5
When 5 is added to a number, we get 15. How do we represent this in the form of an equation in variable x ?
x=15+5
x−5=15
x+15=5
x+5=15
SOLUTION
Solution : D
Let us take the number to be x.
When 5 is added to the number, we get x+5.
Now, we know that when 5 is added to that number, we get 15.
Hence, x+5=15.
Question 6
The variable in the expression (9x+32)÷9 is
SOLUTION
Solution : Variable is the unknown quantity which can have different values at different instances and they are usually represented by alphabets. In above expression, x is the variable.
Question 7
Identify the binomial(s) among the given expressions.
SOLUTION
Solution : A, C, and D
7x +8 xy has two unlike terms. So, it is a binomial.
1 + 2x +3y has three unlike terms. So, it is a trinomial.
3x + 7xy + yx = 3x + 8xy which has two unlike terms. So, it is a binomial.
3x + 2y has two unlike terms. So, it is a binomial.
Question 8
If the sum of successor and predecessor of a number is 14, then the number should be _____.
SOLUTION
Solution : C
Let the number be x.
Therefore, the successor of number is x + 1 and the predecessor is x - 1.
Given that the sum of successor and predecessor is 14.
∴x+1+x−1=14⇒2x=14⇒x=142⇒x=7
So, the number should be 7.
Question 9
Solve for x:x−23=2x7
7
-14
14
-7
SOLUTION
Solution : C
x−23=2x7⇒7×(x−2)=3×2x⇒7x−14=6x⇒7x−6x=14⇒x=14
Question 10
If 2x+10=8x, then the value of x is
−403
3
-40
403
SOLUTION
Solution : A
2x+10=8x⇒2x=8×(x+10)⇒x=4×(x+10)⇒x=4x+40⇒−40=4x−x⇒−40=3x⇒x=−403