# Free Algebra 03 Practice Test - 6th grade

### Question 1

Value of 2xy when x=4 and y=0 is _________.

0

8

16

6

#### SOLUTION

Solution :A

2xy=2× x× y

On substituting the values of x and y, we get2xy=2× 4× 0=8× 0=0

### Question 2

A number when multiplied by 2 and decreased by 41 gives 3. Find the number.

18

20

22

24

#### SOLUTION

Solution :C

Let the number be x.

∴2x−41=3⇒2x=44⇒x=442=22

### Question 3

The coefficient of term xy2 in expression 4xy2+x3−x5+2xy2 is ______.

#### SOLUTION

Solution :D

Since 4xy2 and 2xy2 are like terms, the given expression can be written as follows.

4xy2+x3−x5+2xy2=6xy2+x3−x5

Therefore, the coefficient of xy2 is 6.

### Question 4

Which of the following is a variable?

#### SOLUTION

Solution :C

The temperature of a place in a day at different times will be different. So it is a variable.

The number of days in a week and the number of months in a year always remain the same. So these are constants.

5 has a fixed value. So it is a constant.

### Question 5

When 5 is added to a number, we get 15. How do we represent this in the form of an equation in variable x ?

x=15+5

x−5=15

x+15=5

x+5=15

#### SOLUTION

Solution :D

Let us take the number to be x.

When 5 is added to the number, we get x+5.

Now, we know that when 5 is added to that number, we get 15.

Hence, x+5=15.

### Question 6

The variable in the expression (9x+32)÷9 is

#### SOLUTION

Solution :Variable is the unknown quantity which can have different values at different instances and they are usually represented by alphabets. In above expression, x is the variable.

### Question 7

Identify the binomial(s) among the given expressions.

#### SOLUTION

Solution :A, C, and D

7x +8 xy has two unlike terms. So, it is a binomial.

1 + 2x +3y has three unlike terms. So, it is a trinomial.

3x + 7xy + yx = 3x + 8xy which has two unlike terms. So, it is a binomial.

3x + 2y has two unlike terms. So, it is a binomial.

### Question 8

If the sum of successor and predecessor of a number is 14, then the number should be _____.

#### SOLUTION

Solution :C

Let the number be x.

Therefore, the successor of number is x + 1 and the predecessor is x - 1.

Given that the sum of successor and predecessor is 14.

∴x+1+x−1=14⇒2x=14⇒x=142⇒x=7

So, the number should be 7.

### Question 9

Solve for x:x−23=2x7

7

-14

14

-7

#### SOLUTION

Solution :C

x−23=2x7⇒7×(x−2)=3×2x⇒7x−14=6x⇒7x−6x=14⇒x=14

### Question 10

If 2x+10=8x, then the value of x is

−403

3

-40

403

#### SOLUTION

Solution :A

2x+10=8x⇒2x=8×(x+10)⇒x=4×(x+10)⇒x=4x+40⇒−40=4x−x⇒−40=3x⇒x=−403