Free Basic DI - 05 Practice Test - CAT 

This question can be solved using the Factor of Multiplication(FOM) between both graphs FOM = $\frac{2063520}{1023531}$ = $\frac{20}{10}$ $\approx$ 2

Thus, since the cotton percentage is 32% in the Demand Graph, a similar value in the Supply Graph will be obtained by multiplying 32 with its factor of multiplication (2) = 32 $\times$ 2=64%.

Look at the answer options. Only option (c) – Oil +Food+Plastic =40+23+1= 64%. You can directly mark answer (c)

The answer is based on 1023531 $\times$ 1.1${}^4$ $\approx$ 10${}^2$ $\times$ 11${}^2$ $\times$ 11${}^2$ $\approx$ 10${}^4$ $\times$ 12 $\times$ 12 $\approx$ 14_______

Since there is only one answer option starting with 14, you can mark the answer as option (a)

We know that the total number of articles published in Sept 02> Mar 03. However, we cannot compute if 25% of Sept 02> 37% of Mar 03. The exact values of total number of articles published in the two months or the ratio between the number of articles in September 02 and March 03 is required to solve the question.

Let total number of articles published in December 2002 and June 2003 be ‘x’ and ‘y’ respectively

Then we know that x>y => .19x>.18y

In the products category, percentage is increasing with a decreasing rate i.e.
$\frac{7-3}{3},\frac{10-7}{7},\frac{11-10}{10}$

We cannot determine. Two ratios are possible 1:2 and 1:4.

We can have two possible scenarios.

i) Sachin scores a century against Namibia. Then he scores 6 centuries against Bangladesh. Hence centuries in ODI = 1

ii) Sachin does not score a century against Namibia. Then he scores 7 centuries against Bangladesh. Hence centuries in ODI = 2

So of the given options only option(b) is possible

After concluding only test matches’ centuries, we will get the answer as shown in the table. 

The total number of employees in IT sector = 1800 $\times$ $\frac{13}{100}$= 234

Number of female employees = 1200 $\times$ $\frac{14}{100}$= 168

Number of male employees = 234 – 168 = 66.

Now total number of employees in H.R = 1800 $\times$ $\frac{12}{100}$ = 216

Number of female employees = 1200 $\times$ $\frac{14}{100}$ = 168

Number of male employees = 216 – 168 = 48.

The total number of employees in finance sector = 1800 $\times$ $\frac{20}{100}$ =360

Number of female employees = 1200 $\times$ $\frac{30}{100}$ = 360

Number of male employees = 360 – 360 =0

The total number of employees in operation sector = 1800 $\times$ $\frac{35}{100}$ = 630

Number of female employees = 1200 $\times$ $\frac{30}{100}$ = 360

Number of male employees = 630 – 360 = 270

360:270 = 4:3

Required percentage = $\frac{(168-48)}{48}$ $\times$ 100 = 250%

Temperature gradient in stage II = $\left(\frac{75-25}{100}\right)$ = $\frac{1}{2}$ deg C /min

Temperature gradient in stage III = $\left(\frac{25-(-5)}{90}\right)$ = $\frac{1}{3}$deg C/min

So percentage change = $\left(\frac{0.5-0.33}{0.33}\right)$ = 50%

Initial pressure = 1 bar

Final pressure =0.1 bar

Time = 5 hrs

Rate of change of pressure =$\frac{1-1.01}{5}$ = 0.18 bar/hr

Temperature gradient =$\frac{(35+5)}{5}$= 8 deg C /hr

Pressure gradient = 0.18 bar/hr

So ratio = 800 : 18 = 400 : 9

Difference between Swapnil and Satyendra day wise(Swapnil-Satyendra) -

Monday=-10Tuesday=10 Wednesday=-20Thursday=-30Friday=-20Saturday=40Sunday=40

Therefore, -10 + 10 -20 -30 -20 + 40 + 40 = 10

Average = = 1.428 minutes. Swapnil studied 1.428 more minutes per day than Satyendra.