Free Comparing Quantities Subjective Test 01 Practice Test - 7th grade 

For 6 students we need 3 balls.

$\Rightarrow$ For 1 student, we need $\frac{3}{6}=\frac{1}{2}$  balls.

Therefore, 36 students would need:

$36\times \frac{1}{2}=$ 18 balls.

Units: 1 Mark
Answer: 1 Mark

Given that:
Rashi travelled 6 km.
Soham travelled 5000 m. 
We have to find the ratio of their distance travelled. 
We can only find the ratio if they have the same units.
First, we will convert both the distances to the same unit.

So, $6\text{km}=6\times 1000\text{m}=6000\text{m}$.

Thus, the required ratio is:

 6000 m : 5000 m

$\Rightarrow$ 6:5

Steps: 1 Mark
Answer: 1 Mark

Given that:
In a city, there are 15000 voters.
60% of the voters voted.
Total percentage of voters = 100%

Voters who voted in % = 60%

$\Rightarrow$ Percentage of voters who did not vote
= 100 - 60 = 40%

Total Voters = 15000

40% of 15000 did not vote.

Then, the number of voters who did not vote is:

= 40% of 15000

$\Rightarrow \frac{40}{100}\times 15000=6000$

$\therefore$ 6000 voters did not vote.

Formula: 1 Mark
Answer: 1 Mark

Given that:
Rashi can travel for 4 hours after having a pizza.
Rashid can travel for 6 hours after having a pizza.
Number of hours Rashid travels more after having a pizza = 6 - 4 = 2 hours
In terms of percentage, it is given by, 

$\frac{\text{Extra hours}}{\text{Number of hours Rashi can travel after having a pizza}}\times 100$

On substituting the values we get,

$\frac{2}{4}\times 100=50$

Each option: 1 Mark

Given decimal is,

a) 0.65

$=0.65\times 100\%$

$=\frac{65\times 100}{100}\%=65\%$

b) 2.1

$=2.1\times 100\%$

$=\frac{21\times 100}{10}\%=210\%$

Calculations: 1 Mark
Steps: 1 Mark
Answer: 1 Mark

Let the Fanta, Coca-Cola and Sprite bottles be 8x, 15x, 12x.

The total number of Fanta bottle is 120.

So, 8x = 120

x = 15

Then coca cola bottles $=15\times 15=225$

Sprite bottles $=12\times 15=180$.

So, the total number of bottle is 120 + 225 + 180 = 525.

Alternative Method:
Let '$x$' be the total number of bottles.
Now, the bottles are in the ratio 8: 15: 12
The sum of these numbers = 8 + 15 + 12 = 35
The number of Fanta bottles = 120
Also number of Fanta bottles=$\frac{8}{35}\times x$ = 120
So, $x=\frac{35}{8}\times 120=525$
Hence the total number of bottles is 525.

Formula: 1 Mark
Steps: 1 Mark
Answer: 1 Mark

Number of questions Aarush used to solve initially = 4 questions in 16 minutes
Time needed to solve a question = $\frac{16}{4}$ = 4 minutes

Number of questions Aarush can solve after practising = 6 questions in 18 minutes
Time needed to solve a question = $\frac{18}{6}$ = 3 minutes

Decrease in time to solve a single question = 4 - 3 = 1 minutes.
Therefore, the percentage decrease is given by
Decrease Percent = $\frac{\text{amount decreased}}{\text{Original or base}}\times 100$
On substituting the values, we get:
Decrease in percentage = $\frac{1}{4}\times 100$ = 25%
Hence, after practising Aarush reduced 25% of the time to solve a single question.

Calculations: 1 Mark
Steps: 1 Mark
Answer: 1 Mark

Cost price = ₹ 12000, overhead charges = ₹ 2850

$\therefore$ Total cost price = ₹ (12000 + 2850) = 14850

Selling Price = ₹ 13860

Selling Price < Cost Price $\Rightarrow$ Loss

$\therefore$ Loss = Cost price - Selling price

$\Rightarrow$ Loss = ₹ (14850-13860) = ₹ 990

Loss percentage = $\frac{Loss}{CostPrice}\times 100$

 Loss percentage = $\frac{990}{14850}\times 100$ = 6.7 %

So, Ravi incurred a loss of 6.7%.

Formula: 1 Mark
Steps: 1 Mark
Answer: 1 Mark

Here,
It is given that Soham bought a sofa for Rs6500.
He paid Rs 975 as interest in three years.

Let, Principal amount be 'P' = Rs 6500

Interest be 'I' = Rs 975

Time be 'T' = 3 years

The rate of interest =?
Let the rate of interest be 'R'.

We know that,

$I=\frac{P\times T\times R}{100}$

$\Rightarrow R=\frac{I\times 100}{P\times T}$

$\Rightarrow R=\frac{975\times 100}{6500\times 3}$

$\Rightarrow R=5$
Hence the rate of interest is 5%.

Steps: 2 Mark
Price before discount: 1 Mark
Selling price: 1 Mark

Given that,
Radhika bought a new mobile phone and saved  ₹1000 when a discount of 10$\%$ was given.
We can infer from the above statement that 10$\%$ of the original price =  ₹ 1000

10$\%$ of the original price =  ₹ 1000

Let the price be P.

$\Rightarrow 10\%\text{of P = 1000}$

$\Rightarrow \frac{10}{100}\times \text{P = 1000}$

$\Rightarrow \text{P}=\frac{1000\times 100}{10}$

$\Rightarrow P$ =  ₹ 10000
Hence the original price of the mobile phone is  ₹ 10000.

Now, the original price of the mobile phone is  ₹ 10000.
Discount given =  ₹ 1000
$\therefore$ The Selling price or the price at which the phone was sold = Original Price - Discount
On substituting the values we get:
Selling Price = 10000 - 1000 =  ₹ 9000

Hence, the mobile phone was sold at  ₹ 9000.

Concept: 1 Mark
Steps: 2 Marks
Answer: 1 Mark

Given that:
 Marked price  of the toy = ₹ 200
Discount  =   20%.

Discount = Discount % of Marked Price 

               = $\frac{20}{100}\times 200$

                = ₹ 40
Selling price = Marked Price - Discount 
                    = ₹( 200- 40 ) 

                    = ₹ 160
It is given that even after the discount the shopkeeper was making a profit of 60%.
So, the cost price of the toy
$=\frac{100}{160}\times 160=₹100$

Hence, the actual price of the toy is ₹ 100.

Steps: 2 Marks
Answer: 1 Mark each

Given that:
Meet saves ₹ 4000 from her salary, which is 10% of her salary. 

Let Meet’s salary be ₹  $x$

Given that,

$10\%ofx=4000$

$\frac{10}{100}\times x=4000$

$\frac{x}{10}=4000$

$x=4000\times 10=₹40000$

Therefore, Meet’s salary is ₹ 40,000.

Her net expenditure = Salary - savings = 40000 - 4000 = ₹ 36,000

Now in order to buy a bike Meet starts saving $30\%$ of her salary.
Her salary is ₹ 40,000.
The total amount she starts saving monthly = $\frac{30}{100}\times 40,000$ = $₹12,000$
Her net saving monthly is ₹ 12,000.

Concept: 1 Mark
Steps: 1 Mark
Answer: 1 Mark Each

 Given that,

Cost price = ₹ 2500

Selling price = ₹ 3000

Selling price > Cost price $\Rightarrow$ Profit

$\therefore$ Profit = 3000 - 2500 = ₹ 500

$\text{Profit}\%=\frac{\text{Profit}}{CP}\times 100$

$\text{Profit}\%=\frac{500}{2500}\times 100$

$\text{Profit}\%=20\%$

Now it was sold for ₹ 2000.
The selling price, SP = ₹ 2000
SP<CP
Therefore it is a case of loss.
Loss = CP - SP = 2500 - 2000 = ₹ 500
So, the loss $\%$ is given by, 
Loss $\%$ = $\frac{500}{2500}\times 100$ = 20 $\%$