# Free Decimals 01 Practice Test - 4th Grade

18 as a decimal = ______

A.

125

B.

12.5

C.

1.25

D.

0.125

#### SOLUTION

Solution : D

8's friend is 125 as 8×125=1000

18×125125=1251000=0.125

Find the value.
500+4+4100=___

A. 54.4
B. 54.04
C. 504.4
D. 504.04

#### SOLUTION

Solution : D

We have to do the addition:
=500+4+4100
=500+4+0.04

5 0 0 . 00          4 . 00+      0 . 04––––––––    5 0 4 . 04––––––––

If one pencil costs ₹ 5.75, then the cost of 100 such pencils is _____.

A.

₹ 0.575

B.

₹ 57.50

C.

₹ 575

D.

₹ 5750

#### SOLUTION

Solution : C

Given: Cost of 1 pencil = ₹ 5.75

Cost of 100 pencils = (5.75×100)
Cost of 100 pencils = ₹ 575

1.10.03=    ____

A.

1.7

B.

1.77

C.

1.07

D.

1.70

#### SOLUTION

Solution : C

Since 0.03 has two decimal places, we use the equivalent decimal of 1.1 with two decimal places.

i.e., 1.10.03=1.100.0.3

1 ./10/010 0 .  0   3–––––––––    1 .  0   7––––––––

A shopkeeper wants to distribute 20.7 kgs of sugar into 9 equal jars. How much sugar would go into each jar?

A.

2.7 kg

B.

2.1 kg

C.

2.3 kg

D.

3.1 kg

#### SOLUTION

Solution : C

To find the amount of sugar that goes into each jar, we need to divide 20.7 kg by 9.

20.79 kg=2.3 kg

Each jar will have 2.3 kg of sugar.

Find the value after shifting the decimals.

4.5×1.5 = ____

A.

3.75

B.

4.75

C.

6.75

D.

2.57

#### SOLUTION

Solution : C

We first find 45×15, which is equal to 675.0

Shifting the decimal point two places to the left of 675.0, we get 6.75.

Therefore, 4.5×1.5=6.75.

Six cases of paper cost ₹ 156.49. How much does one cost?

A.

₹ .26.19

B.

₹ 25.45

C.

₹ 26.08

D.

₹ 25.18

#### SOLUTION

Solution : C

cost of six cases = ₹ 156.49

Cost of one case =156.496

156.496=26.08166...

Approximately equal to ₹ 26.08 (Rounding off).

Compare the following and fill in with an appropriate symbol

A.

>

B.

<

C.

=

D.

Not comparable

#### SOLUTION

Solution : C

In the first figure, 27 parts are shaded out of 100 , so the decimal is 0.27
In the second figure, 27 parts are shaded out of 100, so the decimal is 0.27

Hence both the decimals are equal

3×46+4×5125×710 =

A.

56

B.

13

C.

16

D.

35

#### SOLUTION

Solution : C

3×46+4×5125×7103×46+4×5125×71042+5372LCM of 2 ×3=64×32×3+5×23×27×32×312+102122216=16

Find : 3÷67+7÷212 2÷5

A.

31330

B.

32330

C.

32130

D.

31130

#### SOLUTION

Solution : B

3÷67+7÷2122÷53×76+7×2212572+2325LCM of 2, 3, 5 is 3072=7×152×15=1053023=2×103×10=203025=2×65×6=1230105+201230=1133011330=32330