Free Decimals 01 Practice Test - 4th Grade 

 8's friend is 125 as $8\times 125=1000$

$\frac{1}{8}\times \frac{125}{125}=\frac{125}{1000}=0.125$

Given: Cost of 1 pencil = ₹ 5.75

$\therefore$ Cost of 100 pencils $=\text{₹}(5.75\times 100)$
$\Rightarrow$ Cost of 100 pencils = ₹ 575

Since 0.03 has two decimal places, we use the equivalent decimal of 1.1 with two decimal places.

i.e., $1.1-0.03=1.10-\mathrm{0.0.3}$

$1.\text{/}{1}^0\text{/}{0}^{10}\underset{–}{-0.03}\underset{–}{1.07}$

To find the amount of sugar that goes into each jar, we need to divide 20.7 kg by 9.


$\therefore \frac{20.7}{9}\text{kg}=2.3\text{kg}$

$\therefore$ Each jar will have 2.3 kg of sugar.

We first find $45\times 15$, which is equal to 675.0

Shifting the decimal point two places to the left of 675.0, we get 6.75.

Therefore, $4.5\times 1.5=6.75$.

cost of six cases = ₹ 156.49

$\therefore \text{Cost of one case}=\frac{156.49}{6}$

$\frac{156.49}{6}=\mathrm{26.08166...}$

Approximately equal to ₹ 26.08 (Rounding off).

In the first figure, 27 parts are shaded out of 100 , so the decimal is 0.27
In the second figure, 27 parts are shaded out of 100, so the decimal is 0.27

Hence both the decimals are equal 

$3\times \frac{4}{6}+4\times \frac{5}{12}-5\times \frac{7}{10}\frac{3\times 4}{6}+\frac{4\times 5}{12}-\frac{5\times 7}{10}\therefore \frac{4}{2}+\frac{5}{3}-\frac{7}{2}\therefore \text{LCM of 2}\times 3=6\therefore \frac{4\times 3}{2\times 3}+\frac{5\times 2}{3\times 2}-\frac{7\times 3}{2\times 3}12+10-21\frac{22-21}{6}=\frac{1}{6}$

$3÷\frac{6}{7}+7÷\frac{21}{2}-2÷5\therefore 3\times \frac{7}{6}+7\times \frac{2}{21}-\frac{2}{5}\therefore \frac{7}{2}+\frac{2}{3}-\frac{2}{5}LCMof2,3,5is30\therefore \frac{7}{2}=\frac{7\times 15}{2\times 15}=\frac{105}{30}\frac{2}{3}=\frac{2\times 10}{3\times 10}=\frac{20}{30}\frac{2}{5}=\frac{2\times 6}{5\times 6}=\frac{12}{30}\therefore \frac{105+20-12}{30}=\frac{113}{30}\therefore \frac{113}{30}=3\frac{23}{30}$