# Free Decimals 02 Practice Test - 6th grade

I have to walk  2.87 km to attend a party at my friend's house. If I have already walked  1500 m, how many more kilometres do I have to walk?

A.

1.17 km

B.

1.27 km

C.

1.37 km

D.

1.47 km

#### SOLUTION

Solution : C

Total distance = 2.87 km
= 2.87 × 1000 m
= 2870 m
Distance covered = 1500 m

Remaining distance  = 2870 - 1500
= 1370 m

1370 m=13701000=1.37 km

Find the digit at the tenths place in 123.456.

A.

2

B.

6

C.

5

D.

4

#### SOLUTION

Solution : D

Given number is 123.456

Digit in the Hundreds place:       1
Digit in the Tens place:               2
Digit in the Ones place:              3
Digit in the Tenths place:            4
Digit in the Hundredths place:    5
Digit in the Thousandths place:  6

So, the digit at tenths place in 123.456 is 4.

If you have to represent 5 hours and 45 minutes in hours as decimals, how would you do it?

A.

5.04 hours

B.

5.45 hours

C.

5.44 hours

D.

5.75 hours

#### SOLUTION

Solution : D

60 minutes = 1 hour

1 minute = 160 hour

45 minutes = 45 × 160
= 4560
= 0.75 hours

So, 5 hours and 45 minutes =(5+0.75)=5.75 hours

Which of the following lies between 0.754646 and 0.755646?

A. 0.756446
B. 0.756464
C. 0.756647
D. 0.755464

#### SOLUTION

Solution : D

The number between 0.754646 and 0.755646 must be greater than 0.754646 and smaller than 0.755646. In 0.756446, 0.756464 and 0.756647, digits till hundredth place are same but digit at ten thousandth place is greater than that of 0.755646. So, they are greater than 0.755646. So, only 0.755464 can be the answer.

68.2305 + 574.333 + 96.0020 = ____

A.

738.5565

B.

738.6655

C.

738.5655

D.

738.5656

#### SOLUTION

Solution : C

68.2305

+   574.3330

+     96.0020

738.5655
____________

Convert 74 to decimal form.

A.

1.45

B.

1.55

C.

1.65

D.

1.75

#### SOLUTION

Solution : D

Multiplying 74 with 25 on numerator and denominator to make denominator as 100.

=7×254×25

=175100=1.75

74=1.75

Product of 9.52 and 9.82 is ______.

A.

93.4864

B.

9348.64

C.

83.4864

D.

834.864

#### SOLUTION

Solution : A

The product of 9.52 and 9.82 is given by: Here multiplicands have 2 decimal places each. Hence, the product will have 4 digits after the decimal point.
Therefore, 93.4864 is the answer.

Represent 13+710+31000 as a decimal.

A.

13.730

B.

13.307

C.

13.303

D.

13.703

#### SOLUTION

Solution : D

13+710 + 31000=13+0.7+0.003
=13.703

A shopkeeper purchased 15 chocolates for Rs. 100.65. The cost per piece of chocolate is Rs.

___

#### SOLUTION

Solution :

Cost per chocolate = Total costNumber of chocolates
=  100.6515
= Rs. 6.71

The digit at hundredths place in 13.9 is

___.

#### SOLUTION

Solution :

13.9 = 13.90 ;
Therefore, digit at hundredths place = 0.