Free Decimals 02 Practice Test - 4th Grade
Question 1
Find the value:
12+35
4.50
1.10
4.20
0.5
SOLUTION
Solution : B
Decimal form of 12=0.5
Decimal form of 35=0.6
⇒ 0.50 + 0.60––––––– 1.10–––––
Question 2
What fraction in total do the shaded regions represent?
78
32
98
58
SOLUTION
Solution : B
The first part of the figure has a circle divided into 8 parts and 5 parts of it are shaded.
∴ Fraction=58
The second part of the figure has a circle divided into 8 parts and 7 parts of it are shaded.
∴ Fraction=78
Sum=58+78=5+78=128
But, 128=12÷48÷4=32.
∴ The required sum is 32.
Question 3
Find the unknown value.
0.340.2=?
0.17
0.07
1.74
1.70
SOLUTION
Solution : D
We multiply the numerator and denominator of 0.340.2 by 100 to convert them into whole numbers.
0.34×1000.20×100=3420=1710=1.7=1.70
Question 4
Identify the option that has the correct decimal and fraction representation of the shaded region below.
0.4,4100
0.4,410
0.04,410
0.04,4100
SOLUTION
Solution : B
The rectangle is divided into 10 parts, of which 4 are shaded.
∴Fraction =410
But, 410=0.4.
Thus, the correct answer is 0.4,410.
Question 5
Farookh cuts an apple into 12 equal pieces and gives 5 pieces to his best friend. If he eats 4 pieces, what part of the apple is left with Farookh?
0.20
0.25
0.15
0.30
SOLUTION
Solution : B
Farookh eats 4 pieces of the apple and gives 5 pieces to his friend.
∴ Total pieces of apple eaten=512+412=912Remaining pieces=1−912=12−912=312(Reducing by common factor)=3÷312÷3=14Multiply by 25 (both numerator and denominator)=1×254×25=25100=0.25
Question 6
8.25−23100 = ______
3.62
0.38
8.02
0.52
SOLUTION
Solution : C
Convert 23100 into decimal
8.25 - 0.23 = 8.02
Question 7
A member of school team ran for a total of 156.25 miles over 25 days. Approximately how many miles did he run per day?
2
6.25
4
5
SOLUTION
Solution : B
Total miles travelled = 156.25
Number of days they ran = 25 daysMiles they run in a day = 156.25 ÷ 25
So, they ran for 6.25 miles per day for 25 days.
Question 8
Raj bought some sweets. The weighing machine at the shop read 0.25kg. He weighed the sweets again at home, and the reading was 0.250kg. Then:
Machine at shop was faulty
Raju’s machine was faulty
Both machines were correct
He ate some on the way
SOLUTION
Solution : C
The value remains the same if zero is after the numbers.
Question 9
What should be the size of piece that would fit in the unknown region?
112
116
312
316
SOLUTION
Solution : A
34+16
To add the 2 fractions, we need to find the LCM of 4 and 6
LCM of 4 and 6 = 12
34+16=3×34×3+1×26×2=9+212=1112To find the missing piece,
=1−1112=12−1112=112
Question 10
Arrange 13,16,12,17 in ascending order:
12,13,16,17
17,16,13,12
12,16,13,17
17,12,13,16
SOLUTION
Solution : B
17=0.14,16=0.16,13=0.33,12=0.5
or
17,16,13,12
Since the numerators are the same, bigger the denominator smaller the fraction.
7 > 6 > 3 > 2