Free Decimals 02 Practice Test - 5th Grade
Question 1
18 as a decimal =
125
12.5
1.25
0.125
SOLUTION
Solution : D
8's friend is 125 as 8×125=1000
18×125125=1251000=0.125
Question 2
If 24×16=384 then , 2.4×16=
3840
38.4
3.84
0.384
SOLUTION
Solution : B
Given:
24×16=384
Since 24 got divided by 10 to give 2.4, similarly 384 will also be divided by 10 to yeild 38.4
∴2.4×16= 38.4
Question 3
Find the value.
1+11000=____
SOLUTION
Solution : C
We know that
11000= 0.001
So, 1+0.001 = 1.001
Question 4
Find the value.
500+4+4100 = _____
54.4
54.04
504.4
504.04
SOLUTION
Solution : D
We have to do the addition.
500+4+4100=500+4+0.04
5 0 0+ 4+ 0 . 0 4 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯5 0 4 . 0 4–––––––––––
∴ 500+4+4100=504.04
Question 5
The sum of two numbers is 10. If one number is 2.75, then the other number is
7.25
8.25
6.25
8.75
SOLUTION
Solution : A
To find the other number, we have to subtract 2.75 from 10.
0 9 9 10 /1 /0 ./0 /0− 2 . 7 5–––––––––––– 7 . 2 5––––––––––––
Question 6
If one pencil costs ₹ 5.75, then the cost of 100 such pencils is _____.
₹ 0.575
₹ 57.50
₹ 575
₹ 5750
SOLUTION
Solution : C
Given: Cost of 1 pencil = ₹ 5.75
∴ Cost of 100 pencils =₹ (5.75×100)
⇒ Cost of 100 pencils = ₹ 575
Question 7
Find the value.
8÷0.2=
40
4
0.4
0.04
SOLUTION
Solution : A
80.2×1010=802=40
Question 8
Find the value.
0.9×0.9 =
81
8.1
0.81
0.081
SOLUTION
Solution : C
0.9×0.9=910×910
=> 0.9×0.9 = 81100
=> 0.9×0.9 = 0.81
Question 9
Find the value.
0.9×0.83×0.75×0 =
SOLUTION
Solution :Any number multiplied by 0 gives 0 as a result.
So, 0.9×0.83×0.75×0=0
Question 10
Find the unknown value.
0.389×
1000
100
10
1
SOLUTION
Solution : B
We have to find the unknown value which gets multiplied by 0.389 and gives 38.9
→ 0.389×x = 38.9
=> x = 38.9÷0.389
=> x = 38.90.389
=> x = 100