# Free Decimals 02 Practice Test - 5th Grade

18 as a decimal = ______

A.

125

B.

12.5

C.

1.25

D.

0.125

#### SOLUTION

Solution : D

8's friend is 125 as 8×125=1000

18×125125=1251000=0.125

If 24×16=384 then , 2.4×16= _____

A.

3840

B.

38.4

C.

3.84

D.

0.384

#### SOLUTION

Solution : B

Given:

24×16=384

Since 24 got divided by 10 to give 2.4, similarly 384 will also be divided by 10 to yeild 38.4

2.4×16= 38.4

Find the value.
1+11000=____

A. 1.1
B. 1.01
C. 1.001
D. 1.0001

#### SOLUTION

Solution : C

We know that
11000= 0.001

So, 1+0.001 = 1.001

Find the value.

500+4+4100 = _____

A.

54.4

B.

54.04

C.

504.4

D.

504.04

#### SOLUTION

Solution : D

We have to do the addition.
500+4+4100=500+4+0.04

5 0 0+      4+      0 . 0 4    ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯5 0 4 . 0 4–––––––––

500+4+4100=504.04

The sum of two numbers is 10. If one number is 2.75, then the other number is ______ .

A.

7.25

B.

8.25

C.

6.25

D.

8.75

#### SOLUTION

Solution : A

To find the other number, we have to subtract 2.75 from 10.

0    9   9  10     /1 /0 ./0 /0       2 . 7   5––––––––––           7 . 2   5––––––––––

If one pencil costs ₹ 5.75, then the cost of 100 such pencils is _____.

A.

₹ 0.575

B.

₹ 57.50

C.

₹ 575

D.

₹ 5750

#### SOLUTION

Solution : C

Given: Cost of 1 pencil = ₹ 5.75

Cost of 100 pencils = (5.75×100)
Cost of 100 pencils = ₹ 575

Find the value.

8÷0.2= ___

A.

40

B.

4

C.

0.4

D.

0.04

Solution : A

80.2×1010=802=40

Find the value.

0.9×0.9 =____

A.

81

B.

8.1

C.

0.81

D.

0.081

#### SOLUTION

Solution : C

0.9×0.9=910×910

=> 0.9×0.9 = 81100

=> 0.9×0.9 = 0.81

Find the value.

0.9×0.83×0.75×0___

#### SOLUTION

Solution :

Any number multiplied by 0 gives 0 as a result.

So, 0.9×0.83×0.75×0=0

Find the unknown value.

0.389×____ = 38.9

A.

1000

B.

100

C.

10

D.

1

#### SOLUTION

Solution : B

We have to find the unknown value which gets multiplied by 0.389 and gives 38.9

0.389×x = 38.9

=> x = 38.9÷0.389

=> x = 38.90.389

=> x = 100