# Free DI and LR Practice Test - CAT

### Question 1

Who among the four was wearing the yellow cap?

Aman

Dhoni

Boby

Chadni

#### SOLUTION

Solution :B

From statements (i), (ii) and (vi), it can be concluded that Aman was the first person to reach the cinema hall. From statements (i), (ii) and (iv), it can be concluded that Dhoni was wearing the Yellow cap. Hence, either Aman or Boby was wearing the Purple cap and the other one was wearing the White cap. From statement (v), it can be concluded that Aman was wearing the Purple shirt while Boby was wearing the White cap. Further analysis leads to the following table:

Based on the given information we can make a table as shown below:

PositionPersonCap1AmanPurple2DhoniYellow3BobyWhite4ChadniRed

### Question 2

Which of the following statement(s) is/are correct?

I. Aman reached the cinema hall before Boby.

II. Boby wear yellow cap.

I only

II only

Both I and II

Neither I nor II

#### SOLUTION

Solution :A

Option(a)

### Question 3

Who among the four was the last to reach the cinema hall?

Aman

Dhoni

Boby

Chadni

#### SOLUTION

Solution :D

Option(d)

### Question 4

Who among the four was wearing the White cap?

Aman

Dhoni

Boby

Chadni

#### SOLUTION

Solution :C

Option(c)

### Question 5

The high school math department needs to appoint a new chairperson, which will be based on seniority. Ms. "A” has less seniority than Mr. "B”, but more than Ms. "C”. Mr. "D” has more seniority than Ms. "A”, but less than Mr. "B”. Mr. "B” doesn't want the job. Who will be the new math department chairperson?

Mr. "D”

Mr. "B”

Ms. "A”

Ms. "C”

#### SOLUTION

Solution :A

Mr. "B” has the most seniority, but he does not want the job. Next in line is Mr. "D”, who has more seniority than Ms. "A” or Ms. "C”.

### Question 6

What is Dennis' score in Networking?

7.7

8.3

8

Insufficient data

#### SOLUTION

Solution :C

Let us take Chirag's score and find out the weightage given for programming and networking. Chirag's scores in Programming and networking are 8 and 6 respectively. Total marks in Technical skills is 7.2 ie,

So the weightage for programming and networking is 3:2.

Solution : Average score of Dennis in Programming =6+72=6.5.

7.1−6.5x−7.1=23⇒x=8

### Question 7

What are the minimum marks scored by Elizabeth in Interpersonal skills in percentage terms?

33.33%

43%

50%

30%

#### SOLUTION

Solution :B

For Bharat we know that scores of 5,7 and 6 in different sections result in total score of 6 in Soft skills. So it is the simple average.

Hence total marks for Elizabeth in soft skills =8.1×3=24.3She can score maximum of 10 each in the two sections other than Interpersonal skills. So the minimum marks in interpersonal skills is 24.3-20=4.3 which is 43%

### Question 8

What is Elizabeth's total score in the campus recruitment test?

7.3

7.5

7.4

None of these

#### SOLUTION

Solution :A

From Abay's score we can see that scores of 7.7 and 9.2 in technical and soft skills result in a total score of 8.2.

So the weightage is 2:1. So Elizabeth's total score in technical skills, x is

x=6.9

So, Elizabeth's total score is

t=7.3

### Question 9

What is Abhay's score in C++?

8.5

6.6

9.8

9

#### SOLUTION

Solution :D

7.7−6.5x−7.7=32⇒x=8.5 Here x is the average of Java and C++, so score in C++ =9

### Question 10

**Children are in pursuit of a dog whose leash has broken. "A” is directly behind the dog. "B” is behind "A”. "D” is behind "B”. "C” is ahead of the dog walking down the street in the opposite direction. As the children and dog pass, "C” turns around and joins the pursuit. He runs in behind "B”. "A” runs faster and is alongside the dog on the left. "B” runs faster and is alongside the dog on the right. Which child is directly behind the dog?**

A

B

D

C

#### SOLUTION

Solution :D

After all the switches were made, "C” is directly behind the dog, "A” is alongside the dog on the left, "B” is alongside the dog on the right, and "D” is behind "C”. Therefore, option (D) is the correct answer choice.

### Question 11

Watchman A has worked more night shifts in a row than Watchman B, who has worked five. Watchman C has worked fifteen night shifts in a row, more than Watchman A and Watchman B combined. Watchman D has worked eight night shifts in a row, less than Watchman A. How many night shifts in a row has Watchman A worked?

eight

nine

ten

eleven

#### SOLUTION

Solution :B

Watchman A has worked more shifts in a row than Watchman D; therefore, Watchman A has worked more than eight shifts. The number of Watchman A's shifts plus the number of Watchman B's shifts (five) cannot equal fifteen or more, the number of Watchman C's shifts. Therefore, Watchman A has worked nine shifts in a row (5 + 9 = 14). Therefore, option (b) is the correct answer choice.

### Question 12

How many bronze medals did college R win in these five events?

0

1

2

3

#### SOLUTION

Solution :B

Swimming-S, Running-R, Cycling-c, Discus Throw-D and Horse Riding-H

From (i), (v) and (vi), Q won 2 gold medals but not in S or D.

From (iii), T won gold in one from among R or C while T did not win silver in S or D

From (i), S did not win silver in those events in which Q won gold medals. Hence, S did not win any medals in those events.

From (Iv), R won 4 medals and the other colleges won 3 or less medals.

So, the medals won by the remaining 4 colleges are 3, 3, 3 and 2.

T has won 2 medals (i.e., 1 gold and 1 silver (using iii).

P has won 3 medals. So, it must have won 1 gold in silver and 2 bronze in two from among R, C and H.

The gold medals are exhausted as P-1, Q-2, R-1, T-1,

S can win 3 medals: 2 silver and 1 bronze.

Q has won 3 medals: 2 gold among from R, C and H, an 1 bronze.

R won 4 medals: bronze in S, gold in D and 2 silver. There are only three Medal-winning combinations :

Table :- 1

SwimmingRunningCyclingDiscuss ThrowHorse RidingTotalPGBBXX3QXGGBX3RBXSSXGS4SSXXSB3TXSXXSXG2

Table:-2

SwimmingRunningCyclingDiscuss ThrowHorse RidingTotalPGBXXB3QXGXBG3RBXSSGSX4SSXBSX3TXSXGXXS2

Table :- 3

SwimmingRunningCyclingDiscuss ThrowHorse RidingTotalPGXBXB3QXXGBG3RBSXSGSX4SSBXSX3TXGSXXXS2

### Question 13

If college T won a gold in Running and a silver in Cycling, who won a bronze in Horse Riding?

Q

P

R

S

#### SOLUTION

Solution :B

From Table 3, we can determine : -

Hence, P won a bronze medal in Horse Riding.Hence,[b].

### Question 14

Which of the following colleges, won a silver medal in Running? (Refer to the data in previous questions.)

R

P

Q

S

#### SOLUTION

Solution :A

[a]

### Question 15

How many colleges scored the same points in these five events, if 3, 2 and 1 point were given to the winner of a gold, a silver and a bronze medal respectively?

4

2

3

None of these

#### SOLUTION

Solution :C

CollegesPQRSTPoints57855

Thus P,S and T scored 5 points each. Hence, [c].

### Question 16

**Which year had the lowest turnover to net profit ratio?**

2006 - 07

2007 - 08

2008 - 09

2010 - 11

#### SOLUTION

Solution :D

Approximate Turn overto net profit ratios for various years are:

2006-07 = 1503 = 50

2007-08 = 2505 = 50

2008-09 = 2005 = 40

2009-10 = 2607 = 37

2010-11 = 3209 = 35

### Question 17

**In 2007 - 08 if ABC accounted for 7% of industry turnover and the industry turnover saw a growth of 12 % in 2008-09, what was the approximate growth rate ABC's share in industry turnover in 2008-09 over 2007-08?**

+5%

-5%

-28.5%

+28.5%

#### SOLUTION

Solution :C

Total industry turnover in 2008-09 = 250 × (1007) × 112 = 4000 Crores.

So percentage share of ABC in 2008-09 = (2004000) × 100 = 5%

So growth rate = 5−77 × 100 = -28.5%

### Question 18

**What is the average annual growth rate in net profit from 2006-07 to 2010-11?**

25%

50%

75%

100%

#### SOLUTION

Solution :B

The actual values for net profit for various years are 3,5,4.8,7 and 9. So the average annual growth rate = (9−3)×1003×4 = 50%

### Question 19

Three football teams played exactly one match against each other in the Copa America League matches. The table below shows the results of each team after the matches.

TeamWinLostDrawGoalsLost GoalsArgentina20061Brazil01124Chile01136

What was the result of the Argentina-Chile match?

3-1

2-1

4-2

none of these

#### SOLUTION

Solution :D

Chile - Brazil = 2 - 2

Argentina - Chile = 4 - 1

Argentina - Brazil = 2 - 0

### Question 20

**P, Q, R, S, T, and U are six people who form three teams of 2 each . If P is not working with Q or R, Q is not working with R or S, R is not working with Sn or T, then P is working with ?**

S

T

U

Cannot be determined

#### SOLUTION

Solution :A

P can be working with S, T, or U;

Q can be working with T or U and

R can be working with U only.∴ R will be working with U, Q will be working with T and P will be working with S.

### Question 21

If the numbers are arranged in the descending order, which number shall be in the third position?

O

N

M

L

#### SOLUTION

Solution :A

Since P is a even multiple of 11, the possibilities are 22,44,66,88. Out of which 22, 66 and 88 are not possible because P+J=76 and the maximum difference between first & last number can be 16 (given that the numbers are 8 consecutive 2 digit numbers)

Thus P=44.

L+O=74 and O can only be 30 or 40( reason- max. difference between the first & last number = 14 )

O cannot be 30, as L≠44 because P is already 44

Thus O=40, L=34, P=44 and J= 32

We can now see that the range of the numbers is between 30 and 44 or 32 and 46

K needs to end with 0, thus K=30 and the range of numbers is 30-44

Q is an even multiple of 7= 42

Also N2 is odd => N= 38. Thus, M= 36.

option (a) the third number in descending order is O=40

### Question 22

What is the median of the numbers?

38

37.5

36.5

37

#### SOLUTION

Solution :D

The median is the average of the middle 2 numbers =36+382=37. Option (d)

### Question 23

**If the selling price per unit of product B is 527 then what is its profit percentage?**

43.3

13.3

33.3

23.4

#### SOLUTION

Solution :D

Total units of product B = (18100) × 4000 = 720

Total cost = (28100) × 11 = 3.08lakhs

Cost per unit = (3.08720) = 427As the selling price is 527 the profit percentage = 23.4%

### Question 24

**For how many of the five products is the cost per unit more than the average cost of all the given products?**

1

2

3

4

#### SOLUTION

Solution :A

Cost per unit of A = (19100)×11(24100)×4000 = 217

Cost per unit of C = (18100)×11(19100)×4000 = 148

Cost per unit of D = (20100)×11(17100)×4000 = 229

Cost per unit of E = (20100)×11(22100)×4000 = 229

Average cost of all the given products = (217+427+148+229+229)5 = 12505 = 250.

Therefore, only for B, the cost per unit is more than the average cost of all the given products.

### Question 25

What is the difference between the number of trainees at Jacobsons and Robinsons in 2006?

#### SOLUTION

Solution :Year200220032004200520062007∗Trainees220270312351365365Employed1830% of 60=18Recruited18/(30%)=60(312+18)−270=60(365+18)−351=32∗∗Trainees0080190244259Employed30% Of 80=2430% of 110=33Recruited80190−30=110(244+24)−190=78(259+33)−244=48

Note: * → Jacobsons ('00 people)

** → Robinsons ('00 people)Ans: 4600

The difference between the no of recruitments by Jacobsons and Robinsons in 2006 = 7800 - 3200 = 4600

### Question 26

If Jacobsons recruited 7000 freshers as trainees in 2003, what is the difference in no of trainees being actually absorbed as employees at the two firms in 2007?

#### SOLUTION

Solution :Ans: 1500

If Jacobsons recruited 7000 trainees in 2003, then:

Confirmed as employees in 2005 = 2100

More recruited in 2005= 6000

Confirmed as employees in 2007= 1800Robinsons confirmed 3300 trainees as employees in 2007, thus the difference= 3300 -1800=1500.

### Question 27

How many trainees at Robinsons were absorbed as employees by end of 2007?

#### SOLUTION

Solution :No of trainees confirmed by Robinsons by 2007 end = 2400+3300=5700.

### Question 28

From 2008 onwards the no of recruitment of trainees increases by 10% at Jacobsons and 20% at Robinsons. In which year would the no of these new trainees cross 10,000?

#### SOLUTION

Solution :Ans: 2011

The number of fresh recruits would grow as:Year20072008200920102011Jacobsons(′00)365401.5441.65485.82534.4Richardsons(′00)259310.8372.96447.55537.06Total624712.3814.61933.371071.46

### Question 29

What could be the size of the team that includes G?

4

5

6

More than one of the above

#### SOLUTION

Solution :D

The conditions with respect to G are:

ð If G is included, F also must be included

ð If G is included, C and I cannot be included

Thus, some of the possible teams that can be formed are:

a) AEJGDF b) ADGFE c) EGFHMore arrangements are also possible. Hence, it is not possible to determine the size of the team uniquely.

### Question 30

What would be the size of the largest possible team?

4

5

6

7

#### SOLUTION

Solution :C

The largest possible team can have 6 members. As one of (E, B), (D, H) and two of (C, G, I) must definitely be excluded. Therefore, a minimum of 4 members must be excluded to form any team.

### Question 31

Who cannot be included in a team of 6?

A

H

J

E

#### SOLUTION

Solution :B

If a 6 member team is to be formed including H, neither A nor D can be included in that team and further one of (E, B) and two of (C, G, I) must be excluded making the size of the team as 5. Therefore, answer option (b) is the correct answer choice.

### Question 32

What can be the size of the team that includes C?

3

4

5

More than one of the above

#### SOLUTION

Solution :B

If C is included, G, I and F must be excluded.

As F is excluded, J also must be excluded.

As F and I are excluded, the only remaining defender D must be included.

As D is included, A must be included and thus H must be excluded.

As G and H are excluded, the only remaining midfielder B must be included.

As B is included, E must be excluded.Therefore, the team that gets formed is (A, B, C, D).