Free DI and LR Practice Test - CAT 

Profit percent of CompanyY in 1997 = 35.
Let the income of CompanyY in 1997 be Rs. x crores.
Then, 35 = $\frac{x-20}{220}$ $\times$ 100 $\Rightarrow$ x = 297.
Income of CompanyY in 1997 = Rs. 297 crores

Let X's expenditure in 1999 be 100.
We have profit = 50%= $\frac{\text{( Income - 100)}}{100}$
$\Rightarrow$ Income = 150
As per the given information, we have Y's expenditure in 2000 = 150
So, again, $\frac{\text{( Income - 150)}}{150}$ = 50%
$\Rightarrow$ Income = 225

So, the required ratio is 150 : 225 = 2 : 3.

Just by observation, you can be sure that 2008 can be eliminated. Now among 2010 and 2011, the 'Equity' part is same for both of them. To have a higher ratio value, the 'commodity' part should be higher and 'Fixed Income' part should be lower. Thus among these two years, we can again eliminate 2011. The following table will give you the approximate value for years 2009 & 2010.

The maximum population of south India could be 23% of total population i.e. 4,60,000.

Here, Let total consumption of petroleum products in 2010 is x and in 2011 is y.
Now consider the component where the percentage change between the two years is maximum (this is Kerosene)
To compute minimum growth, 12x = 10y, so x = 10 and y = 12,

Growth = $\frac{y-x}{x}$ = 20%.

If kerosene consumption in 2010 is 100 then in 2011 it should be 140. The total consumption in 2010 will be $\frac{2500}{3}$  and in 2011 is 1400. Then the ratio of petrol in 2011 to 2010 is 147:100.

We don't have any link between 2010 and 2011. So, we cannot calculate the ratio of total consumption of petroleum products in 2010 to that in 2011.

Difference in revenue = 432 - 400 = 32 crore.

Percentage increase in the revenue in 2011, as compared to 2009.
= 16 + 7.5 + $\frac{16\times 7.5}{100}$ = 23.5 + 1.2 = 24.7
Required percentage = $\frac{100}{124.7}$ $\times$ 100 = 80% (approximately)

As per the question,the top 3 are ridden by jockeys 6,5 and 4.B is ridden by jockey-6.So from condition (iii), E has to be ridden by jockey-4.Among the top 3, we are only left with jockey 5.But jockey 5 cannot ride C as per condition(iv).Hence option (a)

If Jockey 5 has not been assigned any horse,then E is ridden by jockey 4.Consequently,from condition(iii),B cannot be ridden by Jockey 6.As per condition(iv), we cannot have jockey 7 riding C.So options(a),(c) and (d) are eliminated.

As per the question, jockey 5 has not been assigned any horse and hence E has to be assigned to jockey 4 . So B cannot be assigned to jockeys 2 and 6 as per condition(iii).Also, A or C should be ridden by jockey 1 which leaves us with only one choice wherein B is ridden by jockey 7.Hence option(b).

Option(d) is the right answer.

The fourth condition in the passage tells you that motorbike servicing has to be either immediately before or immediately after jogging. That is, M and J must be ordered as a block, either M J or JM, with respect to the other four activities. Thus, if, as the original third condition states, M has to be earlier than L, then we know that J must also be earlier than L. Conversely, if, as the new condition in answer choice (C) states, J has to be earlier than L, then we know that M must also be earlier than L. In short, the third condition and answer choice (C) have exactly the same effect. Therefore, answer choice (C) is correct.

From the given conditions, we can easily determine "Kitchen cleaning has to be earlier than hedge trimming” Option(d).

Now, Bharat's percentage score in the written test is given by,

$\frac{40+54+70+80}{4}$ = 61%
$\therefore$ $\frac{61x}{100}$+$\frac{76y}{100}$+$\frac{83y}{100}$ = 68.4 $\times$ $\frac{500}{100}$
$\therefore$ 61x + 159y = 34200                  ........(ii)
Multiplying (i) by 61 and subtracting from (ii), we get,
37y = 3700
$\therefore$y = 100
$\therefore$x = 300
$\therefore$x:y = 3:1

So, if Amar scoredxout of 75 in QA, then we have,

x + $\left[\right(50+68+72)\times \frac{75}{100}]$ = 175.5
$\therefore$ 175.5 - 142.5 = 33

According to the given conditions, Daya should have had one mark more than Amar.
∴ Daya got 332.5 out of 500 or 66.5%.
$\therefore$ HIs score in the GD = 332.5 - 77 - $\left[\right(58+78+76+42)\times \frac{75}{100}]$
                                               = 255.5 - 190.5 
                                               = 65

The total marks of Amar and Bharat are 331.5 and 342 respectively, so the difference between them is 10.5.
Now, Eesha's total marks are 
68.8 $\times$ $\frac{500}{100}$ = 344
Out of this, she scored 79 in the GD, 85 in the PI and 
40 $\times$ $\frac{75}{100}$ = 30 in QA 
66 $\times$ $\frac{75}{100}$ = 49.5 in LR 
$\therefore$ Eesha scored 344 - 79 - 85 - 30 - 49.5 = 100.5 in (DI + VA) 

From the given passage, we can conclude that

A -- $P_1$
B -- $P_2$
C -- not $P_4$
D -- not $P_1$ and $P_4$
E -- not $P_2$

If $P_3$ and $P_4$ are sharing flat, then

A -- $P_1$ and $P_5$
B -- $P_2$ and $P_4$
C -- $P_1$ and $P_3$
D -- $P_5$ and $P_2$
E -- $P_3$ and $P_4$

Papaya, Orange, Pineapple, Mango, Banana, Watermelon, Apple

Papaya, Orange, Pineapple, Mango, Banana, Watermelon, Apple

Papaya, Orange, Pineapple, Mango, Banana, Watermelon, Apple

Whenever X occurs, Y occurs, however whenever X does not occur, one cannot say what is true of Y. Therefore AD is valid, but not DA.

If X then Y, which means that if Y has not occurred, then X has not either.

The shortest time is 17 minutes. The key to this problem is that to minimize the time spent; we need to have persons C and D to cross together. However, to avoid one of them having to make the trip back, we need to ensure that when they cross, someone is waiting for them on the other side to take the flashlight back.

Batsmen 9 scored 5. As the two who score 0 are consecutive, batsmen 7 scores 0. Hence Tendulkar has only one slot left, i.e. 6. Now all questions can be answered. 

Batsmen 9 scored 5. As the two who score 0 are consecutive, batsmen 7 scores 0. Hence Tendulkar has only one slot left, i.e. 6. Now all questions can be answered. 

Batsmen 9 scored 5. As the two who score 0 are consecutive, batsmen 7 scores 0. Hence Tendulkar has only one slot left, i.e. 6.