Free DI and LR - 19 Practice Test - CAT 

Question 1

How many students failed in all the five papers?

A. 120
B. 190
C. 260
D. 200
E. none of these

SOLUTION

Solution : E

Consider Electronics, 20% who failed in electronics failed in exactly five, so number of students who failed in all five papers = 20% of 900 = 180. Hence option (e).

Question 2

Of the students who failed in Signals, how many failed in exactly 2 papers?

A. 180
B. 200
C. 150
D. 220
E. cannot be determined

SOLUTION

Solution : A

option (a)

From (1), we know that 180 students failed in all five subjects. So if we take the second row from the top then in all the papers the absolute number is 180, the % value can change depending upon the number of students who failed in that paper. So in Signal, total number of students = 900. Number of students who failed in exactly 5 = 180. So % = (180/900)* 100 = 20%. So, left percentage = 100 – (20 + 20 + 10 + 30) = 20%.

Hence, the number of students who failed in exactly 2 = 20% of 900 = 180.

Question 3

If 20% of the students who failed in C++ failed in exactly 4 papers, then total how many students failed in C++?

A. 400
B. 500
C. 600
D. 680
E. none of these

SOLUTION

Solution : C

Suppose total number of students who failed in C++ = x. 20% of the students failed in exactly 4 subjects, then % of students who failed in exactly 5 subject = 30%. Now 30% of x = 180. So x = 600. So 600 students failed in C++. option c

Question 4

At most how many failed only in Electronics and VLSI.

A. 100
B. 80
C. 60
D. 90
E. none of these

SOLUTION

Solution : D

% of exactly two in electronics is 10%. So 90 students who failed in electronics failed in exactly two papers. Similarly 90 students who failed in VLSI, failed in exactly two papers.So at most 90 failed in Electronics and VLSI. Option d

Question 5

What is the total daily consumption of Captain cook flour?

A. 51.25 m3
B. 53.25 m3
C. 93.10 m3
D. 82.50 m3
E. 38 .25 m3

SOLUTION

Solution : B

option (b) Total consumption/day of Captain cook flour was (6 + 4.5 + 20.25 + 22.5 + 0) = 53.25 m3

Question 6

What percentage of total supermix for the day is used for pastries?

A. 20% 
B. 23%
C. 33%
D. 43%
E. 53%

SOLUTION

Solution : B

option (c) Percentage of total supermix that was used for pastries is = [51/(30+28+51+72+38)*100] = [51/219*100] = 23%

Question 7

The ratio of volume of Captain cook flour to that of Trupti flour consumed daily is:

A. 0.80
B. 0.60
C. 0.70
D. 0.90
E. 1

SOLUTION

Solution : C

option (c) Total daily consumption of Captain cook can be found as follows
for bread the consumption = 30 X (5/10) X (40/100)= 6

Similarly for the other products (6 + 4.5 + 20.25 + 22.5 + 0) = 53.25 m3

While total daily consumption of Trupti+ flour was = 9 + 5.5 + 24.75 + 7.5 + 20 = 66.75 m3

The ratio of volume of Captain cook flour to that of Trupti flour consumed daily is  53.25/66.75 = 0.7

Question 8

On the basis of customer survey, the Cookie &Co. baker, decides to increase the sugar content in the pastries by 100% and reduce the flour content by two thirds and water content by 3/4. What will now be the total volume of the daily consumption of sugar and flour respectively in m3?

A. 76 and 81
B. 81 and 76
C. 93 and 93
D. 110 and 62
E. none of these

SOLUTION

Solution : A

option (a) He increased the sugar content in pastries from 21 to 42 and so the total sugar requirement increased from 55 to 55 + 21 = 76 m3. Further flour content in pastries reduced by 2/3 * 18 = 12m3. Thus flour content became 93 – 12 = 81. Therefore now the total volume of daily consumption of sugar and flour respectively, in m3 becomes 76 and 81 respectively.

Question 9

What is the minimum number of wins with which a person can advance from the 1st module to the second module?

A. 4
B. 5
C. 3
D. 6
E. 2

SOLUTION

Solution : C

Total number of face-offs are 8C2=28. If the highest number of wins in module 1 is 7, then the other person advancing to the next round can win 3 face-offs and qualify. The remaining people can also win 3 face-offs each; totaling to 7+(7*3) =28 face-offs. If 7 members win 2 face-offs, then the total number of points do not add up to 28. Hence, answer is option (c)

Question 10

If Qureshi wins the final module and the total number of revelations in the entire selection process was least, then how many modules did Qureshi win at the most?

A. 4
B. 7
C. 6
D. 9
E. 5

SOLUTION

Solution : B

Qureshi wins the last two modules. We need to maximize the number of games he wins in the first module and minimize the number of revelations.

If he wins 6 face-offs, there are 3 revelations. If he wins 5, there are 2 revelations, and if he wins 4, again there are 3 revelations. Hence, he totally wins 5+1+1=7 games overall. Option (b)

Question 11

If the number of revelations per candidate in the process is maximum 3, who is the least voted candidate who could’ve won?

A. Qureshi
B. Kasturba Wadia
C. Pankaj Chautala
D. David D’souza
E. Jerome Jackson

SOLUTION

Solution : D

option d

Question 12

If more than half the face-offs end up being revelations, who is the highest voted candidate who could’ve won the ticket?

A. Inshatullah
B. Maneckshaw
C. Badrinath
D. A.K.Stevens
E. Chaitra Venkatesan

SOLUTION

Solution : A

Number of face-offs= 28. More than 14 need to be revelations.

Inshatullah can win all the 7 games. The remaining 7 members can win 3 games each totaling to >14 revelations. Answer is option (a)

Question 13

If Bobby Joseph and David D’souza met in the third round, what was the least number of revelations in the whole process?

A. 6
B. 8
C. 7
D. 9
E. 5

SOLUTION

Solution : B

We will have the minimum revelations when the score distribution in both groups are7 5 5 5 3 1 1 1

Assuming rank 1 and rank 2 win all the face-offs in their group. There are no revelations. Rank 9 and 12 win 5 face-offs to advance to the next round. Hence, number of revelations = 2+2=4. Rank 15 and rank 16 win one face-off each = 1+1=2 more revelations in this round

Number of revelations in the next module =2. Hence, total number of revelations= 8. Answer is option (b)

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