Free Exponents and Powers 03 Practice Test - 7th grade
Question 1
Express 343 as a power of 7.
72
73
74
70
SOLUTION
Solution : B
343 can be written as
343=7×7×7
so, 343=73
Question 2
Express 32000 as a product of powers of prime factors.
28×52
28×53
27×54
28×54
SOLUTION
Solution : B
32000 can be written as
32000=(2×2×2×2×2)×1000=25×103
(as 32=2×2×2×2×2)= 25×(2×2×2×5×5×5)
= 25×23×53
= 28×53
Question 3
If a = 2 and b = 3. Find the value of ab×ba.
56
72
64
8
SOLUTION
Solution : B
Putting a=2 and b=3
We get:
23=2×2×2=8 and 32=9
Hence, 8×9=72
Question 4
Find the value of 33×32.
35
343
31
243
SOLUTION
Solution : A and D
Here the two terms have 33 and 32 have different exponents, but the same base.Hence by adding the powers we get,
33×32=33+2 = 35=243
Question 5
Express the given number in standard form:
21700000
2.1×107
2.17×107
1.17×107
1.1701×107
SOLUTION
Solution : B
21700000 can be written as
2.17×10000000=2.17×107
Question 6
The value of 33×23 is:
216
215
201
219
SOLUTION
Solution : A
Expanding the terms:
(3×2)3=63=216
Question 7
(102)2 =
SOLUTION
Solution :From the law of exponent, we have,
(am)n=(a)mn
Therefore,
(102)2=104=10000
Question 8
In 104, 10 is the base and 4 is the
SOLUTION
Solution :Here, 4 is called the exponent.
Question 9
(25)2=−(25)2
True
False
SOLUTION
Solution : B
2252 = 425
−2252 = −425
Hence, the given statement is false.
Question 10
am×bm=(ab)m
True
False
SOLUTION
Solution : A
From the law of exponents, we know that
am×bm=(ab)m
Thus, the given statement is true.