Free Finding Patterns 02 Practice Test - 4th Grade 

$\begin{array}{ccc}I& am& good\\ \downarrow & \downarrow & \downarrow \\ 1& 3& 4\\ Life& is& good\\ \downarrow & \downarrow & \downarrow \\ 5& 2& 4\end{array}$

In both the sentences good is represented as 4.

Hence  good =$\underset{–}{4}$

The given pattern is 3,5,7,9……

Odd numbers are numbers which have 1, 3, 5, 7, 9 in their units place. 

We observe that each term in the above sequence is an odd number, also each term is 2 more than the term preceding it.

So, the above sequence is an example of an odd number pattern.

Prime numbers are the set of numbers which is divisible by 1 or the number itself.

The pattern of prime numbers starting from 7 is

7,11,13,17,19,23,29……

So in this pattern, the number in the 7th position is 29.

So he fed 29 grains to the 7th bird.

1,4,9,16,25,36…….

The square number sequence is a pattern of numbers which is as follows:

The number in nth position = $n\times n$

In the above pattern:

The number in 1st position = $1\times 1$ = 1

The number in 2nd position = $2\times 2$ = 4

The number in 3rd position = $3\times 3$ = 9

The number in 4th position = $4\times 4$ = 16

The number in 5th position = $5\times 5$ = 25

So, the above sequence is a square number pattern.

The given sequence is 1A, 4E, 7I, 10M, 13Q …

We can split the above sequence into two sequences:

1, 4, 7, 10, 13, ...

A, E, I, M, Q, ...

For the number pattern, we observe that each term is 3 more than the preceding term. 

So, the next term in the sequence will be 13 + 3 = 16

The alphabets are:

A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z

The sequence  A, E, I, M, Q, ... the next term in the sequence is obtained by skipping three alphabets and jumping to the fourth one, starting with A.

So, the next alphabet in the sequence is U.

On combing the sequence of the numbers and the alphabets, next term in the sequence is 16U.

So, the pattern is 1A, 4E, 7I, 10M, 13Q, 16U, ...

The given sequence is  2, 8, 14, 20…

Let us calculate the difference between two consecutive terms:

8 - 2 = 6

14 - 8 = 6

20 - 14 = 6

We observe that the difference between two consecutive terms is 6 and each term is 6 more than the term preceding it.

So,the ${10}^{th}$ term of the sequence = 2 + (10 - 1)$\times$6 = 2 + 9$\times$6 = 2 + 54 = 56

Hence, the ${10}^{th}$ term of the sequence is 56.

In the pattern above, the arrow flips by 90${}^{\circ }$ in clockwise direction.

So the next figure in the pattern will be

In the pattern above, a red arrow is followed by two green arrows. 

So, the next two figures in the above pattern are a red arrow followed by a green arrow.