Free Fractions and Decimals 02 Practice Test - 7th grade
Question 1
Solve 13−(56×918)+29.
436
536
636
736
SOLUTION
Solution : B
13−(56×918)+29
=13−(1536)+29
=13−1536+29
Taking L.C.M of denominators, 12−15+836=536
Question 2
12×(1+14)×(1+24)×(1+34)×(1+54) is equal to:
44256
948255
1890512
945256
SOLUTION
Solution : C and D
12×(1+14)×(1+24)×(1+34)×(1+54)
= 12 ×54×64×74×94=945256
Question 3
Find the least fraction, which must be multiplied to (124 −12 +3616 −116 +28) to make it an integer.
241
161
731
173
SOLUTION
Solution : B
(124 -12 +3616 -116 +28)
=64 −12 +5416 −116 +28
Taking LCM of denominators and solving,
24 −8 +54 −1 +416=7316
Now, If we multiply 7316 by 161, it becomes 73, which is an integer
Hence, 161 is the required fraction.
Question 4
The value of (12)×(12)+(12)(21)×(12)×(34) is
SOLUTION
Solution :(12)×(12)+(12)(12)+(12)×(34) = (14)+(12)1×(34) = (34)(34)=1
Question 5
[514−25×559+(12+34)] is equal to:
916
7718
2412
1224
SOLUTION
Solution : B
Given [514−25×559+(12+34)]
Apply BODMAS rule to solve= [214−(25×509)+54]
= [214−(209)+54]
Taking LCM of denominators, we have
189−80+4536=15436=7718
[514−25×559+(12+34)]=7718
Question 6
A person bought 312 kg of apples, 223 kg of grapes and 113 kg of oranges. He wants to divide them among 4 people. Find the amount of fruits(in kg) that each person will receive.
138 kg
158 kg
178 kg
278 kg
SOLUTION
Solution : C
First, let us do the conversion of mixed fractions into improper fractions.
i.e 312=(2×3)+12=72
223=(3×2)+23=83, and
113=(3×1)+13=43
Total quantity of fruits=(72+83+43) kg
=72+4
=72+82 kg
=152 kgWhen 152 kg is divided among 4 people,
each person's share =1524kg
=(152×14)kg
=158 kg
=178 kg
Hence, each person gets (178) kg of fruits.
Question 7
212+213+214110×25×1256 is equals to:
5.5
6.5
7.5
8.5
SOLUTION
Solution : D
52+73+94110×25×1256
=851256=8512×65
=172=8.5
Question 8
Varun travelled 18th of the journey which is equal to 56km on a scooter . What is the remaining distance he has to cover?
342 km
392 km
352 km
442 km
SOLUTION
Solution : B
Let the total distance to be covered =d km
Then, 18×d = 56kmd = (56×8)km = 448km
Remaining distance = (448 - 56)km = 392km
Question 9
The product of two fractions is 20. If one of the fractions is 14, then the other fraction is
SOLUTION
Solution : Let the other fraction be x
Then, x×14=20
x=20×4=80
Question 10
Simplify the following expression and choose the correct answer:
0×(59×23)+56×9×0(45+35+12)
910
49
1
0
SOLUTION
Solution : D
Concentrate on numerator. The expression has '0' multiplied to it, and any number multiplied by '0' is '0'.
And 0 divided by any number always '0'.
Hence the answer is '0'.