# Free Fractions and Decimals 03 Practice Test - 7th grade

(0.89345×1000)+8.9345893.45=

A.

89.345

B.

8.9345

C.

893.45

D.

8934.50

#### SOLUTION

Solution : B

Shifting the decimal point 3 places to the right of the decimal number 0.89345, we have
0.89345×1000=893.45

(0.89345×1000)+8.9345893.45
=893.45+8.9345893.45
=0+8.9345
=8.9345

(12.4+9.6)×(0.1 +0.001) _____ (1.24×10.96)×0.2

A.

>

B.

<

C.

=

D.

can't say

#### SOLUTION

Solution : B

(12.4+9.6)×(0.1 +0.001)

=22.0×0.101

=2.222

And, (1.24×10.96)×0.2

=13.59×0.2

=2.718

2.718 is greater than 2.222

Therefore, (12.4+9.6)×(0.1 +0.001)  < (1.24×10.96)×0.2

The length of a cuboid is 0.3m. Its breadth and height is 0.03m and  0.003m respectively. The volume of the cuboid is given as the product of its length, breadth and height. The volume of cuboid is:

A.  0.0027m3
B.  2.7×105m3
C.  2.7×104m3
D.  0.000027m3

#### SOLUTION

Solution : B and D

Given, length = 0.3m

height = 0.003m

Volume = 0.3×0.03×0.003m3

=0.000027m3

(60×0.06×6)(0.0006×600×0.6) is equal to:

A.

21.384

B.

213.84

C.

2.1834

D.

20.484

#### SOLUTION

Solution : A

(60×0.06×6)(0.0006×600×0.6)

=(21.6)(0.216)

=21.384

A bag contains 25 kg of rice at ₹ 20.04 per kg and 20 kg of dal at ₹ 15.28 per kg. What is the total cost of 5 such bags?

A.

4033

B.

4038.36

C.

4038.92

D.

4040.40

#### SOLUTION

Solution : A

Cost of rice in one bag = 25×20.04

= 501

Cost of dal in one bag = 20×15.28

= 305.6

Total cost of one bag = 501 + 305.6

= 806.6

Cost of 5 such bags = 5×806.6

= 4033

Convert the following fractions into decimals and find the sum of these decimals that rounded up to 2 decimal places.

12, 52, 49, 520, 310, 7100, 1002, 10000010000000, 1248, 999, 525
Ans: ___

#### SOLUTION

Solution :

12=0.5

52=2.5

49=0.4444

520=0.25

310=0.3

7100=0.07

1002=50

10000010000000=0.01

1248=0.25

999=0.09090909

525=0.20

Sum = 54.615

When rounded up to two decimal place,

Then Sum = 54.62

0.010.001+0.0010.01 equals ______.

A.

10.101

B.

100.1

C.

10.01

D.

10.1

#### SOLUTION

Solution : D

0.010.001=0.01×10.001=0.01×10001

=10

0.0010.01=0.001×10.01=0.001×1001

= 0.1

0.010.001+0.0010.01 =10+0.1=10.1

On multiplying a decimal number by 100, we shift the decimal point  (i) ______  places to the  (ii) ______  and on dividing a decimal number by 100, we shift the decimal point,  (iii)_______  places to the  (iv) _______.

A.

i) two ii) left iii) two iv) right

B.

i) one ii) right iii) one iv) left

C.

i) two ii) right iii) one iv) left

D.

i) two ii) right iii) two iv) left

#### SOLUTION

Solution : D

Let's take an example and visualize.

2.48×100=248.0 [Decimal point shifted two places to the right]

2480÷100=2480100=24.80 [Decimal point shifted two places to the left]

Find the value of 722 correct up to 4 decimal places.

A.

0.3183

B.

0.3182

C.

0.3180

D.

0.1830

#### SOLUTION

Solution : B Now, the 5th decimal place is greater than 5. So, we add 1 to the previous digit, which gives 0.3182

Hence, the required answer is 0.3182.

4 kg of fruits are shared equally among 5 children. How many grams of fruits does each child get?

A.

700 g

B.

800 g

C.

80 g

D.

70 g

#### SOLUTION

Solution : B

Total weight of fruits = 4 kg
Total number of children among whom the fruits are to be shared equally = 5
Thus, the total quantity of fruits each child would get = 45 kg

= 45 ×1000 grams

=40005g

= 800 g