Free Mensuration 01 Practice Test - 6th grade
Question 1
The given figure is a combination of
a square and a triangle.
a triangle and a hexagon.
a triangle and a pentagon.
a pentagon and a square.
SOLUTION
Solution : C
The given figure has two parts, the lower part is a triangle and the upper part is a pentagon.
Question 2
Which of the following options correctly describes the given figure?
It is a regular figure.
It is closed.
Number of sides can be found out.
It is an open figure.
SOLUTION
Solution : B
Given figure is an irregular figure, for which the number of sides cannot be found out. The figure is also a closed one.
Question 3
How many sides we have to cover in order to make a complete round of the given figure?
4
14
12
10
SOLUTION
Solution : C
The given figure has a total of 12 sides (AB, BC, CD, DE, EF, FG, GH, HI, IJ, JK, KL and LA). In order to complete a full round, one should reach the same corner one started from. So, we have to cover 12 sides.
Question 4
The sum of all the sides of a closed figure is called its
SOLUTION
Solution :The sum of all the sides of a closed figure is termed its perimeter.
Question 5
The perimeter of a square is
SOLUTION
Solution :The perimeter is the total length of the boundary of the closed figure. For a square, it is basically the sum of all the sides and in a square, all sides are equal. So, the perimeter is 4 x sides.
Question 6
Find the perimeter of the following figure (all measurements are in mm):
128.82 mm
26.72 cm
27.72 mm
27.72 cm
SOLUTION
Solution : C
Perimeter = Sum of lengths of all sides
∴ Perimeter of the given figure = 4.3 mm + 1.52 mm + 5.4 mm + 9.2 mm + 3.1 mm + 4.2 mm
= 27.72 mm
Question 7
Calculate the perimeter of the given figure -
29.2 cm
35.6 cm
30 cm
28.4 cm
SOLUTION
Solution : B
In the given figure, sides FE and ED are unknown.
Now, FE + GH + CD = AB = 5.6 cm
⇒ 1.2 + 0.8 + FE = 5.6
⇒ FE = 3.6 cm
GF = ED = 5.8 cm and AH = BC = 6.4 cmPerimeter of the figure is sum of all sides
= HG + GF + FE + ED + DC + CB + BA + AH
= 1.2 cm + 5.8 cm + 3.6 cm + 5.8 cm + 0.8 cm + 6.4 cm + 5.6 cm + 6.4 cm
= 35.6 cm
Question 8
The area of the rectangle with length 11 cm and width equal to half its length will be
22 cm2
33 cm2
60.5 cm
60.5 cm2
SOLUTION
Solution : D
Width of rectangle = 112 cm
Area of rectangle= length × Width
= 112×11
= 60.5 cm2
Question 9
There is a square plot with side length equal to 13 m. A farmer wanted to grow grass on half his field and plough the remaining land. Find the area of land used to grow the grass.
84.5 m2
169 m2
52 m2
84.5 m
SOLUTION
Solution : A
Given, side of the square plot = 13 m
We know that, area of a square = Side x Side
So, total area of a square
= Side × Side
= 13 x 13 = 169 m2Area on which grass is grown = Half of the total area
= 1692 = 84.5 m2
Question 10
The area of a rectangular piece of a board is 36 cm2. If the length is 4 cm, what is the width of the board?
26 cm
4 cm
9 cm
12 cm
SOLUTION
Solution : C
Area of rectangle = length × breadth
∴ 36 = 4 × breadth
⇒364 = breadth
⇒ breadth = 9 cm