Free Mensuration 02 Practice Test - 6th grade 

The length of the boundary of a closed figure is called its perimeter.

Hence, perimeter is the distance covered along the boundary forming a closed figure when you go round the figure once. 

Perimeter is basically the total length of the boundary of a figure. This is valid for closed figures only (both regular and irregular).

The perimeter of a figure is the sum of lengths of all sides. In other words, perimeter is the distance covered along the boundary of the figure when you go round the figure once.

Perimeter of a rectangle
= 2 $\times$ (Length + Breadth)
= 2 $\times$ ( 10 inches + 5 inches )
= 30 inches.

Perimeter = Sum of all the sides
Since it is a regular octagon, all sides will be equal.
$\therefore$ Perimeter = 8 $\times$ length of a side
                     = 8 $\times$ 15 cm
                     = 120 cm

Area of square = Side $\times$ Side
                      = 14 $\times$ 14
                      = 196 $c{m}^2$

Perimeter of square = 4 $\times$ length of side
                             = 4 $\times$ 15
                             = 60 cm

Given a square room of side = 6 m.
Area of each tile = 0.5 m²  
We know that, area of a square = Side $\times$ Side
$\therefore$ Area of a square room
= 6 $\times$ 6 = 36 m².

So, number of tiles required
= $\frac{\text{Area of room}}{\text{Area of a single tile}}$
= $\frac{36}{0.5}$ = 72
Hence, Karan should buy 72 tiles to cover the floor of his room.

Area of rectangular field
= length $\times$ breadth
= 12 $\times$ 5
= $60{\text{m}}^2$

Cost of ploughing
= Total area $\times$ cost per sq. metre 
= $60\times 12$
= ₹ 720

Area of the figure = Area of A + Area of B + Area of C
Area of rectangle $=length\times breadth$

A , B & C are rectangles  
$=3\times 6+4\times (6-3)+2\times 6$ 
$=(3\times 6)+(4\times 3)+(2\times 6)$
= $18+12+12=42sq.units$