# Free Mensuration 02 Practice Test - 6th grade

### Question 1

Perimeter is the distance covered along the boundary forming a/an________ when you go round the figure once.

open figure

closed figure

line

#### SOLUTION

Solution :C

The length of the boundary of a closed figure is called its perimeter.

Hence, perimeter is the distance covered along the boundary forming a closed figure when you go round the figure once.

### Question 2

Perimeter is not valid for

irregular and closed figures

all closed figures

closed regular figures

open figures

#### SOLUTION

Solution :D

Perimeter is basically the total length of the boundary of a figure. This is valid for closed figures only (both regular and irregular).

### Question 3

Perimeter of any figure is

Sum of lengths of sides

Product of length of all sides

Square of lengths of all sides

None of these

#### SOLUTION

Solution :A

The perimeter of a figure is the sum of lengths of all sides. In other words, perimeter is the distance covered along the boundary of the figure when you go round the figure once.

### Question 4

A rectangle has a length of 10 inches and breadth of 5 inches. The perimeter of the rectangle will be

30 square inches

30 inches

15 square inches

15 inches

#### SOLUTION

Solution :B

Perimeter of a rectangle

= 2 × (Length + Breadth)

= 2 × ( 10 inches + 5 inches )

= 30 inches.

### Question 5

The perimeter of a regular octagon with each side measuring 15 cm is

275 cm

100 cm

120 cm

None of above

#### SOLUTION

Solution :C

Perimeter = Sum of all the sides

Since it is a regular octagon, all sides will be equal.

∴ Perimeter = 8 × length of a side

= 8 × 15 cm

= 120 cm

### Question 6

The area of a square of side 14 cm will be:

42 cm2

28 cm2

196 cm^{2}

56 cm2

#### SOLUTION

Solution :C

Area of square = Side × Side

= 14 × 14

= 196 cm2

### Question 7

The perimeter of a square of side 15 cm will be:

90 cm

60 cm

225 cm

34 cm

#### SOLUTION

Solution :B

Perimeter of square = 4 × length of side

= 4 × 15

= 60 cm

### Question 8

Karan wants to cover the floor of his room with lavish tiles. His room is square in shape with sides of 6 m. The shopkeeper told him that the area of each tile is 0.5 m^{2}. Can you tell how many tiles Karan should buy?

108

36

72

144

#### SOLUTION

Solution :C

Given a square room of side = 6 m.

Area of each tile = 0.5 m^{2 }

We know that, area of a square = Side × Side

∴ Area of a square room

= 6 × 6 = 36 m^{2}.So, number of tiles required

= Area of roomArea of a single tile

= 360.5 = 72

Hence, Karan should buy 72 tiles to cover the floor of his room.

### Question 9

Find the cost of ploughing a rectangular farm at the rate of ₹ 12/m^{2} , having length equal to 12 m and width equal to 5 m.

₹ 120

₹ 720

₹ 360

₹ 240

#### SOLUTION

Solution :B

Area of rectangular field

= length × breadth

= 12 × 5

= 60 m2Cost of ploughing

= Total area × cost per sq. metre

= 60×12

= ₹ 720

### Question 10

The area of given figure is:

#### SOLUTION

Solution :B

Area of the figure = Area of A + Area of B + Area of C

Area of rectangle =length×breadthA , B & C are rectangles

=3×6+4×(6−3)+2×6

=(3×6)+(4×3)+(2×6)

= 18+12+12=42 sq. units