Free Mensuration 02 Practice Test - 6th grade 

Question 1

Perimeter is the distance covered along the boundary forming a/an________ when you go round the figure once. 

A.

open figure

B. open curve
C.

closed figure

D.

line

SOLUTION

Solution : C

The length of the boundary of a closed figure is called its perimeter.

Hence, perimeter is the distance covered along the boundary forming a closed figure when you go round the figure once. 

Question 2

Perimeter is not valid for

A.

irregular and closed figures

B.

all closed figures

C.

closed regular figures

D.

open figures

SOLUTION

Solution : D

Perimeter is basically the total length of the boundary of a figure. This is valid for closed figures only (both regular and irregular).

Question 3

Perimeter of any figure is

A.

Sum of lengths of sides

B.

Product of length of all sides

C.

Square of lengths of all sides

D.

None of these

SOLUTION

Solution : A

The perimeter of a figure is the sum of lengths of all sides. In other words, perimeter is the distance covered along the boundary of the figure when you go round the figure once.

Question 4

A rectangle has a length of 10 inches and breadth of 5 inches. The perimeter of the rectangle will be 

A.

30 square inches 

B.

30 inches

C.

15 square inches

D.

15 inches   

SOLUTION

Solution : B

Perimeter of a rectangle
= 2 × (Length + Breadth)
= 2 × ( 10 inches + 5 inches )
= 30 inches.

Question 5

The perimeter of a regular octagon with each side measuring 15 cm is

A.

275 cm

B.

100 cm

C.

120 cm

D.

None of above

SOLUTION

Solution : C

Perimeter = Sum of all the sides
Since it is a regular octagon, all sides will be equal.
Perimeter = 8 × length of a side
                     = 8 × 15 cm
                     = 120 cm

Question 6

The area of a square of side 14 cm will be:

A.

42 cm2

B.

28 cm2

C.

196 cm2

D.

56 cm2

SOLUTION

Solution : C

Area of square = Side × Side
                      = 14 × 14
                      = 196 cm2

Question 7

The perimeter of a square of side 15 cm will be:

A.

90 cm

B.

60 cm

C.

225 cm

D.

34 cm

SOLUTION

Solution : B

Perimeter of square = 4 × length of side
                             = 4 × 15
                             = 60 cm

Question 8

Karan wants to cover the floor of his room with lavish tiles. His room is square in shape with sides of 6 m. The shopkeeper told him that the area of each tile is 0.5 m2. Can you tell how many tiles Karan should buy? 

A.

108

B.

36

C.

72

D.

144

SOLUTION

Solution : C

Given a square room of side = 6 m.
Area of each tile = 0.5 m2  
We know that, area of a square = Side × Side
Area of a square room
= 6 × 6 = 36 m2.

So, number of tiles required
= Area of roomArea of a single tile
= 360.5 = 72
Hence, Karan should buy 72 tiles to cover the floor of his room.

Question 9

Find the cost of ploughing a rectangular farm at the rate of ₹ 12/m2 , having length equal to 12 m and width equal to 5 m.

A.

₹ 120

B.

₹ 720

C.

₹ 360

D.

₹ 240

SOLUTION

Solution : B

Area of rectangular field
= length × breadth
= 12 × 5
= 60 m2

Cost of ploughing
= Total area × cost per sq. metre 
= 60×12
=
₹ 720

Question 10

The area of given figure is:

A. 41 sq. units
B. 42 sq. units
C. 24 sq. units
D. 40 sq. units

SOLUTION

Solution : B

Area of the figure = Area of A + Area of B + Area of C
Area of rectangle =length×breadth

A , B & C are rectangles  
=3×6+4×(63)+2×6 
=(3×6)+(4×3)+(2×6)
= 18+12+12=42 sq. units