Free Mensuration Subjective Test 02 Practice Test - 6th grade 

Concept: 1 Mark

The perimeter is the distance covered along the boundary forming a closed figure when you go round the figure once.

Steps: 1 Mark
Answer: 1 Mark

Area of the field
= $10\times 2$
= $20f{t}^2$

Area covered by one bag of soil
=$10f{t}^2$

$\therefore$ No. of bags required

= $\frac{\text{Area of the field}}{\text{Area covered by one bag of soil}}=\frac{20}{10}=2$ 

Hence, Preeti need 2 bags.

Steps: 1 Mark
Answer: 1 Mark

Let the breadth of the notebook be $ycm$
Length = 15 cm (Given)
Perimeter = 50 cm (Given)
Perimeter of the rectangular notebook = Sum of the lengths of its four sides.

$\Rightarrow 50=15+15+y+y$

$\Rightarrow 50=2(15+y)$

$\Rightarrow 25=(15+y)$

$\Rightarrow y=10$

$\therefore$ The width of notebook is $10cm$

Area covered by the notebook

$=15cm\times 10cm$

$=150c{m}^2$

Pentagon: 1 Mark
Steps: 1 Mark
Answer: 1 Mark

Pentagon has 5 sides.


Given that each side of the pentagon $=30m$

The perimeter of a regular pentagon

= $5\times$ length of each side

= $5\times 30$

= $150m$

Hence, the distance covered by Shakshi is $150m.$

Steps: 1 Mark
Formula: 1 Mark
Answer: 1 Mark

Area of the living room

= length $\times$ breadth = $9m\times 9m=81m^2$

The cost per $m^2$  = ₹12

Cost for $81m^2=12\times 81=₹972$

Steps: 2 Marks
Answer: 1 Mark


Perimeter of the figure will be:

= 3 cm + 6 cm + 3 cm + 3 cm + 10 cm + 3 cm + 2 cm + 3 cm + 2 cm + 3 cm 
(Starting from the topmost edge and going clockwise)
$=38cm$

Steps: 2 Marks
Formula: 1 Mark
Answer: 1 Mark

The perimeter of an equilateral triangle:

= 3 $\times$ length of a side.
 

The total distance to be painted:

= 3 $\times$ 4 = 12 km        
 

$\Rightarrow$ Hence, the total cost for painting:

= 250 $\times$ 12

= Rs 3000


$\Rightarrow$ Area of the garden

= $\frac{1}{2}\times$ base $\times$ height.

= $\frac{1}{2}\times \frac{4}{2}\times 3.46$

= 3.46 km${}^2$

Each Option: 2 Marks

(a) Area of a rectangular garden:
= length $\times$ breadth = 18
= 3 $\times$ breadth

$\Rightarrow$ breadth = $\frac{18}{3}$
= 6 m

(b) Perimeter = 2 $\times$ (length + breadth)
= 2 $\times$ (3+6) = 18m${}^2$

Steps: 2 Marks
Formula: 1 Mark
Answer: 1 Mark

The area of the figure can be calculated in three steps:

i) Find the area of the small rectangle.

ii) Find the area of the large rectangle.

iii) Find the area of the triangle

i) Area of the small rectangle:
= length $\times$ breadth
= 5 $\times$ 6
= 30 inches${}^2$
 

ii) Area of the large rectangle:
= 12 $\times$ 4
= 48 inches${}^2$
 

iii) Area of the triangle:
= $\frac{1}{2}\times$ (height $\times$ base)
= $\frac{1}{2}\times$ 4 $\times$ 3 = 6 inches${}^2$

Area of the shape = Area of the small rectangle + Area of the large rectangle + Area of the triangle
= (30 + 48 + 6) inches${}^2$= 84 inches${}^2$