Free Perimeter and Area 02 Practice Test - 4th Grade 

Given:

The breadth of a rectangle = 7 cm
Area of the rectangle = 63 $c{m}^2$

Area of a rectangle = length $\times$ breadth 
63 $c{m}^2$ = length $\times$ 7 cm
$\text{length}=\frac{Area}{breadth}$
$=\frac{63c{m}^2}{7cm}$
$=9cm$

Given: Side of the Square = 10 m 
Since Ali is running around the park, he runs along the boundary i.e. the perimeter of the park.
Perimeter of a square = 4 $\times$ Side
= 4 $\times$ 10 m
= 40 m
Distance covered by Ali in two rounds of the park = 2 $\times$ Perimeter
= 2 $\times$ 40 m
= 80 m

Given that
Perimeter of the square = 40 cm

Perimeter of a square = 4 $\times$ Side
$\Rightarrow 40cm=4\times \text{Side}$
$\text{Side}=\frac{40cm}{4}=10cm$
 

Perimeter of a square = 4 $\times$ Side

Given: Perimeter = 12 cm

$\Rightarrow$ 12 cm = 4 $\times$ Side

$\Rightarrow$ Side = $\frac{12}{4}$ = 3 cm

The area of a square = side $\times$ side

=3 cm $\times$ 3 cm

= 9 $c{m}^2$

In the given figure, we have 7 rectangles that are shaded.


Since, area occupied by each rectangle =  1 $c{m}^2$
Therefore, area occupied by 7 rectangles (shaded region) =  $7\times 1c{m}^2$ = $7c{m}^2$

It will be more than the perimeter of square because in the case of square, we consider 4 sides but in the case of triangle, we have 6 sides to consider since each triangle has 3 sides.

Area of a rectangle = Length $\times$ Breadth

= 4 $\times$ 5

= 20 $c{m}^2$

Area of the square = Side $\times$ Side
Given: Side = 11 cm
$\therefore$ Area = 11 cm $\times$ 11 cm = 121 $c{m}^2$

The metre is the SI unit and hence, sq. m is in the SI units of area.

There are 4 squares of side 8 cm.
When we keep the squares next to each other, the length of the side will be $8\times 4$ = 32 cm and the breadth will be 8 cm.
Hence, it will form a rectangle of length 32 cm and breadth of 8 cm.
$\therefore$ perimeter of the rectangle
= 2(length + breadth)
= 2(32 + 8)
= 80 cm