Free Perimeter, Area and Volume 02 Practice Test - 5th Grade

Question 1

If the dimensions of a box is $6 m \times 4 m \times 5 m$ , then its volume is:

$120 m^{3}$

$158 m^{3}$

$132 m^{3}$

$128 m^{3}$

SOLUTION

Solution : A

$V o l u m e o f t h e b o x = L e n g t h \times B r e a d t h \times H e i g h t$
$= 6 m \times 4 m \times 5 m$
$= 120 m^{3}$
Therefore, volume of the box will be $120 m^{3}$ .

Question 2

If the perimeter of a square is 16 cm, then its area is:

$4 c m^{2}$

$8 c m^{2}$

$16 c m^{2}$

$32 c m^{2}$

SOLUTION

Solution : C

Given: Perimeter = 16 cm
Perimter of a square = 4 $\times$ Side
$\Rightarrow$ 16 cm = 4 $\times$ Side
$\Rightarrow$ Side $= \frac{16}{4} = 4 c m$

Area of a square = Side $\times$ Side
$\Rightarrow$ Area of the square $= 4 c m \times 4 c m = 16 c m^{2}$

Question 3

Find the perimeter of the triangle given below.

150 cm

90.8 cm

170 cm

90.08 cm

SOLUTION

Solution : C

We know that 1 m = 100 cm
$\Rightarrow$ 0. 8 m = 0.8 $\times$ 100 cm = 80 cm

Perimeter = Sum of all sides = AB + BC +AC
$\Rightarrow$ Perimeter = 50 cm + 40 cm + 80 cm = 170 cm

Question 4

If the area of a rectangle is 63 $c m^{2}$ and its breadth is 7 cm, then the length of the rectangle is:

6 cm

7 cm

8 cm

9 cm

SOLUTION

Solution : D

Given:
Breadth of a rectangle = 7 cm
Area of the rectangle = 63 $c m^{2}$

Area of rectangle = Length $\times$ Breadth
$\Rightarrow$ Length = $\frac{A r e a}{B r e a d t h}$
$\Rightarrow$ Length = $\frac{63 c m^{2}}{7 c m} = 9 c m$

Question 5

If the dimensions of a brick is $20 c m \times 10 c m \times 5 c m$ , then the volume of two such bricks will be ____ $c m^{3}$ .

1000

2000

3000

4000

SOLUTION

Solution : B

Given: Dimensions of a brick is $20 c m \times 10 c m \times 5 c m$ .

Volume of the brick $= l e n g t h \times b r e a d t h \times h e i g h t = 20 c m \times 10 c m \times 5 c m = 1000 c m^{3}$
Volume of two bricks $= 2 \times 1000 c m^{3} = 2000 c m^{3}$

Question 6

A rectangle is formed by keeping two squares next to each other. The length of the sides of each square is 10 cm.

What is the area of the rectangle formed by these two squares?

100 c m^{2}

200 c m^{2}

300 c m^{2}

400 c m^{2}

SOLUTION

Solution : B

Given: The length of the sides of each square is 10 cm.
For the rectangle formed:
Length = 10 cm + 10 cm = 20 cm
Breadth = 10 cm
Area of the rectangle = Length $\times$ Breadth = $20 c m \times 10 c m = 200 c m^{2}$

Question 7

If the perimeter of a square is 40 cm, then find the length of its side.

A. 5 cm

B. 10 cm

C. 160 cm

D. 80 cm

SOLUTION

Solution : B

Given: Perimeter of the square = 40 cm
Perimeter of a square = $4 \times S i d e$
$\Rightarrow$ $4 \times S i d e = 40 c m$
$\Rightarrow$ $S i d e = 10 c m$

$∴$ If the perimeter of a square is 40 cm, then the length of its side will be 10 cm.

Question 8

If the volume of a cube is $1000 c m^{3}$ , then the length of its side will be:

100 c m

100 c m^{2}

10 c m

10 c m^{2}

SOLUTION

Solution : C

Given: Volume of the cube: $1000 c m^{3}$
Volume of a cube = $S i d e^{3}$
$\Rightarrow$ $S i d e^{3} = 1000 c m^{3}$
$\Rightarrow$ $S i d e = 10 c m$
Therefore, the length of the side will be 10 cm.

Question 9

Length and breadth of a rectangle are 10 cm and 5 cm. Find its area.

A. 15 cm

15 c m^{2}

C. 2 cm

50 c m^{2}

SOLUTION

Solution : D

Given: Length of the rectangle = 10 cm
Breadth of the rectangle = 5 cm
Area of a rectangle = Length $\times$ Breadth
= $10 c m \times 5 c m$
= $50 c m^{2}$
Therefore, area of the given rectangle is $50 c m^{2}$ .

Question 10

The side of a cube is 4 cm long. Find its volume.

64 c m^{3}

16 c m^{3}

32 c m^{3}

64 c m^{3}

SOLUTION

Solution : D

Given: Length of each side = 4 cm
Volume of a cube = $S i d e^{3}$
= $(4 c m)^{3}$
= $64 c m^{3}$
Therefore, volume of the given cube is $64 c m^{3}$ .

Free Perimeter, Area and Volume 02 Practice Test - 5th Grade

Question 1

SOLUTION

Question 2

SOLUTION

Question 3

SOLUTION

Question 4

SOLUTION

Question 5

SOLUTION

Question 6

SOLUTION

Question 7

SOLUTION

Question 8

SOLUTION

Question 9

SOLUTION

Question 10

SOLUTION

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