Free Playing with Numbers 01 Practice Test - 5th Grade
Question 1
Choose the correct order according to BODMAS:-
÷, ×, + −
×, ÷, +, −
÷, +, ×, −
×, ÷, −, +
SOLUTION
Solution : A
Brackets
Of
Division
Multiplication
Addition
Subtraction
According to BODMAS, Division (÷), is done before Multiplication (×), which is followed by Addition (+) & and then by Subtraction (−).
Question 2
Identify the number which is divisible by 2.
2223
2002
2117
2085
SOLUTION
Solution : B
Only even numbers are divisible by 2. No odd number is divisible by 2. Hence 2002 is the number divisible by 2.
Question 3
When 2 even numbers are multiplied, the product is always
Odd
Even
Zero
Infinity
SOLUTION
Solution : B
When any 2 even numbers are multiplied
eg. 2×8=16 or 12×12=144, the product is always an even number.
Question 4
(18×50)+(18×9)=18×?
18
95
59
9
SOLUTION
Solution : C
Applying Distributive property of multiplication over addition to simplify:
(18×50)+(18×9)
=18×(50+9)=18×59
Question 5
Estimate to the nearest thousand:
3460×7599
2,40,00,000
24,00,000
2,10,00,000
21,00,000
SOLUTION
Solution : A
3460 × 7599
3460 can be rounded off to 3000,
as 3460 < 3500
7599 is rounded off to 8000,
as 7599 > 7500
Hence the estimate is
3000 × 8000
3 × 8 = 24 followed by 6 zeroes = 2,40,00,000
Question 6
Increase 216 by 93 and then decrease by 9. Identify the solution.
309
301
310
300
SOLUTION
Solution : D
216 Increased by 93
= 216 + 93 ––––––––––––– 309 ––––––––––––
309 decreased by 9
= 309 − 9 –––––––––– 300 ––––––––––
Hence "300" is the answer.
Question 7
If 640+360 apples were kept in 50 boxes. How many apples were there in each box if all boxes had equal number of apples?
20
10
25
50
SOLUTION
Solution : A
640+360 apples make 1000 apples
640+ 360 ––––––– 1000 –––––––
1000 apples equally divided into 50 boxes
= 1000÷50=100/05/0
=1005=20 apples in each box.
Alternate Method
1000÷50=20 apples in each box
Question 8
What is the sum of the numbers between 40 and 50, that are exactly divisible by 7.
92
93
91
90
SOLUTION
Solution : C
The numbers between 40 and 50 that are exactly divisible by 7 ( those numbers that can be divided by 7, without leaving a remainder) are 42 and 49.
42=7×6
49=7×7
The sum of 42 and 49 is 91
42+49––––– 91 –––––
Hence "91" is the sum.
Question 9
The product of 2 whole numbers is 48 and their sum is less than 15. What are the 2 possible numbers?
1,48
4,12
3,16
6,8
SOLUTION
Solution : D
The product of 2 whole numbers is 48.
Given below are the pairs of factors of 48 and their sum.
1×4848+1=492×2424+2=263×1616+3=194×1212+4=166×88+6=14
Hence "6,8" are the possible numbers.
Question 10
A number 21978 is multiplied by a 1 digit number to get a product where the digits are exactly reversed. Identify the 1 digit number.
2
4
6
9
SOLUTION
Solution : B
21978 when reversed gives 87912. So the units digit of the product must be 2.
In the original number, the unit digit is 8. To get 2 in the unit digit in the product, 8 must be multiplied with either 4 or 9.
8×4=32 or 8×9=72
The tens digit in the reversed number 87912 is 1. To get that, we need to multiply by 4.
2 31 39 37 8× 4 –––––––––– 8 7 9 1 2 –––––––––––––
Hence, 21978 is multiplied by '4' to get a product where the digits are exactly reversed.