# Free Playing with Numbers 01 Practice Test - 5th Grade

### Question 1

Choose the correct order according to BODMAS:-

÷, ×, + −

×, ÷, +, −

÷, +, ×, −

×, ÷, −, +

#### SOLUTION

Solution :A

Brackets

Of

Division

Multiplication

Addition

Subtraction

According to BODMAS, Division (÷), is done before Multiplication (×), which is followed by Addition (+) & and then by Subtraction (−).

### Question 2

Identify the number which is divisible by 2.

2223

2002

2117

2085

#### SOLUTION

Solution :B

Only even numbers are divisible by 2. No odd number is divisible by 2. Hence 2002 is the number divisible by 2.

### Question 3

When 2 even numbers are multiplied, the product is always

Odd

Even

Zero

Infinity

#### SOLUTION

Solution :B

When any 2 even numbers are multiplied

eg. 2×8=16 or 12×12=144, the product is always an even number.

### Question 4

(18×50)+(18×9)=18×?

18

95

59

9

#### SOLUTION

Solution :C

Applying Distributive property of multiplication over addition to simplify:

(18×50)+(18×9)

=18×(50+9)=18×59

### Question 5

Estimate to the nearest thousand:

3460×7599

2,40,00,000

24,00,000

2,10,00,000

21,00,000

#### SOLUTION

Solution :A

3460 × 7599

3460 can be rounded off to 3000,

as 3460 < 3500

7599 is rounded off to 8000,

as 7599 > 7500

Hence the estimate is

3000 × 8000

3 × 8 = 24 followed by 6 zeroes = 2,40,00,000

### Question 6

Increase 216 by 93 and then decrease by 9. Identify the solution.

309

301

310

300

#### SOLUTION

Solution :D

216 Increased by 93

= 216 + 93 ––––––––––––– 309 ––––––––––––

309 decreased by 9

= 309 − 9 –––––––––– 300 ––––––––––

Hence "300" is the answer.

### Question 7

If 640+360 apples were kept in 50 boxes. How many apples were there in each box if all boxes had equal number of apples?

20

10

25

50

#### SOLUTION

Solution :A

640+360 apples make 1000 apples

640+ 360 ––––––– 1000 –––––––

1000 apples equally divided into 50 boxes

= 1000÷50=100/05/0

=1005=20 apples in each box.

Alternate Method

1000÷50=20 apples in each box

### Question 8

What is the sum of the numbers between 40 and 50, that are exactly divisible by 7.

92

93

91

90

#### SOLUTION

Solution :C

The numbers between 40 and 50 that are exactly divisible by 7 ( those numbers that can be divided by 7, without leaving a remainder) are 42 and 49.

42=7×6

49=7×7

The sum of 42 and 49 is 91

42+49––––– 91 –––––

Hence "91" is the sum.

### Question 9

The product of 2 whole numbers is 48 and their sum is less than 15. What are the 2 possible numbers?

1,48

4,12

3,16

6,8

#### SOLUTION

Solution :D

The product of 2 whole numbers is 48.

Given below are the pairs of factors of 48 and their sum.

1×4848+1=492×2424+2=263×1616+3=194×1212+4=166×88+6=14

Hence "6,8" are the possible numbers.

### Question 10

A number 21978 is multiplied by a 1 digit number to get a product where the digits are exactly reversed. Identify the 1 digit number.

2

4

6

9

#### SOLUTION

Solution :B

21978 when reversed gives 87912. So the units digit of the product must be 2.

In the original number, the unit digit is 8. To get 2 in the unit digit in the product, 8 must be multiplied with either 4 or 9.

8×4=32 or 8×9=72

The tens digit in the reversed number 87912 is 1. To get that, we need to multiply by 4.

2 31 39 37 8× 4 –––––––––– 8 7 9 1 2 –––––––––––––

Hence, 21978 is multiplied by '4' to get a product where the digits are exactly reversed.