# Free Playing with Numbers 01 Practice Test - 5th Grade

Choose the correct order according to BODMAS:-

A.

÷, ×, +

B.

×, ÷, +,

C.

÷, +, ×,

D.

×, ÷, , +

#### SOLUTION

Solution : A

Brackets

Of

Division

Multiplication

Subtraction

According to BODMAS, Division (÷), is done before Multiplication (×), which is followed by Addition (+) & and then by Subtraction ()

Identify the number which is divisible by 2.

A.

2223

B.

2002

C.

2117

D.

2085

#### SOLUTION

Solution : B

Only even numbers are divisible by 2. No odd number is divisible by 2. Hence 2002 is the number divisible by 2.

When 2 even numbers are multiplied, the product is always

A.

Odd

B.

Even

C.

Zero

D.

Infinity

#### SOLUTION

Solution : B

When any 2 even numbers are multiplied

eg. 2×8=16 or 12×12=144, the product is always an even number.

(18×50)+(18×9)=18×?

A.

18

B.

95

C.

59

D.

9

#### SOLUTION

Solution : C

Applying Distributive property of multiplication over addition to simplify:

(18×50)+(18×9)

=18×(50+9)=18×59

Estimate to the nearest thousand:

3460×7599

A.

2,40,00,000

B.

24,00,000

C.

2,10,00,000

D.

21,00,000

#### SOLUTION

Solution : A

3460 × 7599

3460 can be rounded off to 3000,

as 3460 < 3500

7599 is rounded off to 8000,

as 7599 > 7500

Hence the estimate is

3000 × 8000

3 × 8 = 24 followed by 6 zeroes = 2,40,00,000

Increase 216 by 93 and then decrease by 9. Identify the solution.

A.

309

B.

301

C.

310

D.

300

#### SOLUTION

Solution : D

216 Increased by 93

=       216       + 93   –––––––––––           309  ––––––––––

309 decreased by 9

=    309       9  ––––––––        300  ––––––––

If 640+360 apples were kept in 50 boxes. How many apples were there in each box if all boxes had equal number of apples?

A.

20

B.

10

C.

25

D.

50

#### SOLUTION

Solution : A

640+360 apples make 1000 apples

640+ 360 –––––  1000 –––––

1000 apples equally divided into 50 boxes

= 1000÷50=100/05/0

=1005=20 apples in each box.

Alternate Method 1000÷50=20 apples in each box

What is the sum of the numbers between 40 and 50, that are exactly divisible by 7.

A.

92

B.

93

C.

91

D.

90

#### SOLUTION

Solution : C

The numbers between 40 and 50 that are exactly divisible by 7 ( those numbers that can be divided by 7, without leaving a remainder) are 42 and 49.

42=7×6

49=7×7

The sum of 42 and 49 is 91

42+49–––     91 –––

Hence "91" is the sum.

The product of 2 whole numbers is 48 and their sum is less than 15. What are the 2 possible numbers?

A.

1,48

B.

4,12

C.

3,16

D.

6,8

#### SOLUTION

Solution : D

The product of 2 whole numbers is 48.

Given below are the pairs of factors of 48 and their sum.

1×4848+1=492×2424+2=263×1616+3=194×1212+4=166×88+6=14

Hence "6,8" are the possible numbers.

A number 21978 is multiplied by a 1 digit number to get a product where the digits are exactly reversed. Identify the 1 digit number.

A.

2

B.

4

C.

6

D.

9

#### SOLUTION

Solution : B

21978 when reversed gives 87912. So the units digit of the product must be 2.

In the original number, the unit digit is 8. To get 2 in the unit digit in the product, 8 must be multiplied with either 4 or 9.

8×4=32  or  8×9=72

The tens digit in the reversed number 87912 is 1. To get that, we need to multiply by 4.

2 31 39 37 8×            4 ––––––––     8 7 9 1 2 –––––––––––

Hence,  21978 is multiplied by '4' to get a product where the digits are exactly reversed.