Free Practical Geometry 01 Practice Test - 7th grade
Which of the following options is/are correct when a transversal intersects two parallel lines?
Solution : A, B, and C
If two lines are parallel then:
Corresponding angles are equal i.e., ∠a=∠e
Alternate interior angles are equal i.e., ∠c=∠f
Alternate exterior angles are equal i.e., ∠b=∠g
Vertically opposite angles are equal in case of intersecting lines.
Two angles are complementary when they add up to 90 degrees.
Statement 1: When two lines intersect each other, only the angles forming linear pair are supplementary.
Statement 2: When two lines intersect each other, angles forming linear pair are supplementary.
Choose the correct option.
Solution : C
Statement 2 is correct while statement 1 is incorrect.
Reason:-If the lines are perpendicular to each other, then the pair of vertically opposite angles are also supplementary.
Which of the following data is not sufficient to draw a unique triangle?
Solution : A and C
When all the angles of a triangle are given, then you won't be able to draw a unique triangle. To get a unique triangle at least one side of a triangle should be given.
When two side and included angle is given then, then any unique triangle can be drawn.
Similarily in case of two angles and an included side, a unique triangle can be drawn.
You are given the measurement of two sides of a right angled triangle such that these sides enclose the right angle. What else do you need in order to draw a triangle?
Solution : D
If the lengths of the two sides enclosing the right angle in a right-angled triangle are given, we do not require any more data to draw the triangle.
Ram drew ∠ABC and then he drew a line segment BD such that the line segment BD is angle bisector of ∠ABC. Then, ∠(ABC)=
Solution : As stated in question line segment BD is angle bisector so, ∠ABD=∠DBC
If there are four line segments of length3cm, 7cm, 14cm and 21cm. Then how many triangles can be drawn from these line segments?
The condition to form a triangle is that sum of the lengths of two sides of a triangle must be greater than the third one.
Consider 3 cm , 7 cm and 14 cm ;
3 + 7 ≯ 14 cm
Similarily if we consider other combination 7 ,14 ,21 , 14 + 21 ≯ 7
Hence no triangles can be formed.
If ∠ACD= 90o. Then line segment AB is
When a line segment is perpendicular to another line segment then angle between them is 90o.
Akash tried to make a ΔABC whose rough figure is given below.
He first drew BC. Then taking B as a centre he drew 7cm arc and C as a centre he drew a 3cm arc.
Will he be able to get the point A? Yes or No.
The sum of any two sides of a triangle is greater than the third side.
Here, 7cm+3cm=10cm, which is less than 14cm. So, a triangle can't be constructed.
Therefore, Akash will not get the arcs intersecting at any point.
Kushagra drew two lines, l and m parallel to each other. He drew another line n which is parallel to m. His friend Manish says that the line n will be parallel to line l as well.Manish is correct.
Solution : A
If two lines are parallel then a line drawn parallel to the one of them will be parallel to the other line too.
Pavan drew two lines and he measured some angles. He found that ∠1=∠5 and so he concluded that the two lines are parallel.
State whether his conclusion is true or false.
Solution : A
If two lines are parallel to each other, then the corresponding angles formed when a transversal passes through them are equal. By the converse of the previous statement, if the corresponding angles are equal, then the lines must be parallel. So, Pavan's conclusion is true.