Free Understanding Elementary Shapes Subjective Test 02 Practice Test - 6th grade 

Given that
The length of the line segment AB = 5m
The length of the line segment BC = 4m
The length of the line segment AC = 9m
The length of AB+BC = 9m = AC

According to the given conditions, AB + BC = AC. So, B lies in between A and C.

Each option: 1 Mark

When the hour hand completes one complete revolution it completes 360 degrees.

a) When the hour hand moves from 3 to 6 it covers 90 degrees. When it moves from 6 to 8 it covers 60 degrees. So, the angle covered when hour hand moves from 3 to 8 is 150 degrees.

Fraction that it has moved = $\frac{150}{360}$ = $\frac{5}{12}$

b) When the hour hand of the clock moves from 3 to 9 it moves through two right angles.
So the angle it covers when it moves from 3 to 9 = 180 ${}^{\circ }$
Fraction that it has moved = $\frac{180}{360}$ = $\frac{1}{2}$

Each Point: 1 Mark

We know that a right angle is equal to 90${}^{\circ }$
a) Any angle less than a right angle is an acute angle.
b) If an angle is greater than 90${}^{\circ }$ and less than 180${}^{\circ }$, then it is called an obtuse angle.
If an angle is greater than 180${}^{\circ }$ then it is called a reflex angle.

Visualisation: 1 Mark
Finding the angle: 1 Mark
Type of Triangle: 1 Mark

The minute hand covers an angle of 30${}^{\circ }$ in every five minutes. The angle covered in moving from 4 to 6 is 60${}^{\circ }$.
The length of the minute hand remains constant. So the two sides of the triangle will be equal. 
So the angles will be same for the sides which are equal.

Now, the angle included between the sides whose length are equal is 60${}^{\circ }$.
So the other angles are (180-60)$÷$2 = 60${}^{\circ }$.
Hence all the angles of the triangle are 60${}^{\circ }$.
$\therefore$ The the triangle formed is an equilateral triangle.

Steps: 2 Marks
Answer: 1 Mark

The angle covered when the minute hand moves from 3 to 6 is 90 degrees.

Given that:

The sides of the quadrilateral are equal.
So the quadrilateral can either be a rhombus or a Square.
But the angles included between the sides is 90${}^{\circ }$.
$\therefore$ The quadrilateral is a Square.

Now in a square, the diagonals intersect each other at 90${}^{\circ }$.
So angle between the diagonals is 90${}^{\circ }$

Steps: 2 Marks
Answer: 1 Mark

Given that:
ABCD is a rectangle.
E and F are the mid-points of the lines AC and BD respectively.
$\therefore$AE=BF=EC=FD
Also, AH=HB=CG=GD   [ H is mid point of AB , G is midpoint of CD ]
$\angle$A, $\angle$B, $\angle$C and $\angle$D are right angles.
The four sides of  rectangle formed i.e. EHFG will have equal dimensions. 
$\therefore$The length of all their diagonals will also be same.
EH=HF=FG=EG
All sides of the quadrilateral are equal.
So either it will be a Rhombus or a Square.
But for both of these quadrilaterals, the diagonals intersect at a right angle.
 The angle formed between the diagonals is a right angle.

Steps: 2 Marks
Actual Reading: 1 Mark
Angle Rotated: 1 Mark

The minute hand when points at 6 cover an angle of 180 degrees.

As per question reading of the minute hand moved is twice the actual reading.

So, it will be pointing at 3.

Now for every five minutes, the minute hand would rotate through 30${}^{\circ }$.
So when the minute hand passes from 12 to 3, total minutes passed =15.
Therefore the actual angle rotated by the minute hand = 3$\times$30 = 90${}^{\circ }$