If the least common multiple of two numbers, 1728 and K is 5184,
| If the least common multiple of two numbers, 1728 and K is 5184, then how many values of K are possible?
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Right Answer is: D
The uncommon factor of K and 1728 = 5184/1728 = 3
Let K = 2a x 3b
Now, because we take maximum powers of the prime factors in the L.C.M
Hence K is a multiple of and power to 2 is less than 6.
Total possible values of m are
Hence number of possible values of K are 7.