If x=(a/b) + (b/a), y = (b/c) + (c/b) and z = (c/a) + (a/c), then

| If x=(a/b) + (b/a), y = (b/c) + (c/b) and z = (c/a) + (a/c), then what is the value of xyz - x2 - y2 - z2 ?
A. -4
B. 2
C. -1
D. -6
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Right Answer is: A
SOLUTION
Let the a=b=c
Then x=2
Y=2
Z=2
So xyz-x2-y2-z2=2× 2×2 – 4 – 4 - 4= - 4