3x–5y=49x=2y+7Solve the above equations by elimination

$3 x - 5 y = 4$
$9 x = 2 y + 7$

Solve the above equations by elimination method and find the value of x.

$x = \frac{9}{13}$

$x = \frac{5}{13}$

$x = \frac{- 5}{13}$

$x = \frac{7}{13}$

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$3 x - 5 y = 4$ ......(1)

$9 x = 2 y + 7$
$9 x - 2 y = 7$ .....(2)

On multiplying equation (1) by 3, we get

$9 x - 15 y = 12$ .......(3)

On subtracting (2) from (3), we get

$- 13 y = 5$

$\Rightarrow y = \frac{- 5}{13}$

On substituting the value of $y$ in (2), we get

$9 x = 2 y + 7$

$\Rightarrow x = \frac{7 + 2 y}{9}$

$\Rightarrow x = \frac{7 - \frac{10}{13}}{9}$ = $\frac{81}{13 \times 9}$

$\Rightarrow x = \frac{9}{13}$