A 1N755 Zener diode is connected (in reverse biased mode) in seri
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| A 1N755 Zener diode is connected (in reverse biased mode) in series to a 620 Ω resistor and a 20 V DC supply. Calculate the diode current.
A. 20.16 mA
B. 12.16 mA
C. 28.49 mA
D. 30.12 mA
Please scroll down to see the correct answer and solution guide.
Right Answer is: A
SOLUTION
Concept:
A 1N755 is a 400 mW silicon linear diode with a Zener breakdown voltage of 7.5 V, i.e. the voltage across the Zener diode after breakdown remains constant at 7.5 V.
Analysis:
The given situation can be drawn as:
Applying KVL across the circuit we get:
20 - VZ - 620 × I = 0
20 - 7.5 - 620 × I = 0
620×I = 12.5
\(I=\frac{12.5}{620}A\)
I = 20.16 mA