A broadcast radio transmitter radiates 5 kW when the modulation p
| A broadcast radio transmitter radiates 5 kW when the modulation percentage is 80. How much of this is carrier power?
A. 4 kW
B. 3.8 kW
C. 3.6 kW
D. 6.25 kW
Please scroll down to see the correct answer and solution guide.
Right Answer is: B
SOLUTION
Concept:
The total transmitted power for an AM system is given by:
\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)
Pc = Carrier Power
μ = Modulation Index
Calculation:
Given Pt = 5 kW
μ = 0.8
\(5~kW = {P_c}\left( {1 + \frac{{{0.8^2}}}{2}} \right)\)
\(5~kW = {P_c}\times{1.32}\)
\(P_c=\frac{5~k}{1.32}=3.78~kW\)
Pc ≈ 3.8 kW