A concentrated load P acts on a simply supported beam of span L a
| A concentrated load P acts on a simply supported beam of span L at a distance L/4 from the left end. The bending moment at the point of application of load is given by:
A. PL/4
B. 3PL/9
C. 3PL/16
D. PL/16
Please scroll down to see the correct answer and solution guide.
Right Answer is: C
SOLUTION
R1 + R2 = P
R2 × L = P × L/4
R2 = P/4
R1 = 3P/4
Bending moment at the point of applied load:
\({M_P} = {R_1} \times \frac{L}{4} = \frac{{3P}}{4} \times \frac{L}{4} = \frac{{3PL}}{{16}}\)