A tuning fork vibrates with 2 vibrations in 0.4 seconds. Its freq
![A tuning fork vibrates with 2 vibrations in 0.4 seconds. Its freq](/img/relate-questions.png)
| A tuning fork vibrates with 2 vibrations in 0.4 seconds. Its frequency is
A. 5
B. 6
C. 8
D. 2.5
Please scroll down to see the correct answer and solution guide.
Right Answer is: A
SOLUTION
CONCEPT:
- Frequency (f): The number of waves that pass a given point per second is called frequency.
- The unit of frequency is vibration per second or Hertz.
-
Time period (T): The time taken to complete one full oscillation or cycle by the Wave is called time period.
-
The SI unit of the time period is second (s).
-
The relationship between time period and frequency is given as:
Time period (T) = 1/f
CALCULATION:
Number of vibrations = 2
Time for 2 vibrations = 0.4 sec
So the time for 1 vibration = 0.4/2 = 0.2 sec
Time period (T) = 0.2 sec
Frequency (f) = 1/T = 1/0.2 = 5 Hz
So option 1 is correct.