Calculate the distribution factor for a single layer 18 slots 2-p
![Calculate the distribution factor for a single layer 18 slots 2-p](/img/relate-questions.png)
A. <span class="math-tex">\(3 \times \frac{{sin30^\circ }}{{sin10^\circ }}\)</span>
B. <span class="math-tex">\(3 \times \frac{{sin10^\circ }}{{sin30^\circ }}\)</span>
C. <span class="math-tex">\( \frac{{sin10^\circ }}{{3\;sin30^\circ }}\)</span>
D. <span class="math-tex">\( \frac{{sin30^\circ }}{{3\;sin10^\circ }}\)</span>
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Right Answer is: D
SOLUTION
Concept:
Distribution factor \({k_d} = \frac{{sin\frac{{m\gamma }}{2}}}{{m\sin \frac{\gamma }{2}}}\)
Where \(m = \frac{{slots}}{{pole \times phase}}\)
\(\gamma = \frac{{\pi \times p}}{s}\)
P = no of poles
S = no of slots
Calculation
No of slots = 18
No of poles = 2
No of phase = 3
\(m = \frac{{18}}{{2 \times 3}} = 3\)
\(\gamma = \frac{{\pi \times 2}}{{18}} = 20^\circ\)
\({k_d} = \frac{{sin\frac{{3 \times 20}}{2}}}{{3\;sin\frac{{20}}{2}}} = \frac{{sin30^\circ }}{{3\;sin10^\circ }}\)