Calculate the distribution factor for a single layer 18 slots 2-p

Calculate the distribution factor for a single layer 18 slots 2-p
| Calculate the distribution factor for a single layer 18 slots 2-pole three-phase stator winding 

A. <span class="math-tex">\(3 \times \frac{{sin30^\circ }}{{sin10^\circ }}\)</span>

B. <span class="math-tex">\(3 \times \frac{{sin10^\circ }}{{sin30^\circ }}\)</span>

C. <span class="math-tex">\( \frac{{sin10^\circ }}{{3\;sin30^\circ }}\)</span>

D. <span class="math-tex">\( \frac{{sin30^\circ }}{{3\;sin10^\circ }}\)</span>

Please scroll down to see the correct answer and solution guide.

Right Answer is: D

SOLUTION

Concept:

Distribution factor \({k_d} = \frac{{sin\frac{{m\gamma }}{2}}}{{m\sin \frac{\gamma }{2}}}\)

Where \(m = \frac{{slots}}{{pole \times phase}}\)

\(\gamma = \frac{{\pi \times p}}{s}\)

P = no of poles

S = no of slots

Calculation

No of slots = 18

No of poles = 2

No of phase = 3

\(m = \frac{{18}}{{2 \times 3}} = 3\)

\(\gamma = \frac{{\pi \times 2}}{{18}} = 20^\circ\)

\({k_d} = \frac{{sin\frac{{3 \times 20}}{2}}}{{3\;sin\frac{{20}}{2}}} = \frac{{sin30^\circ }}{{3\;sin10^\circ }}\)