During charging of a capacitor of C = 100 μf through a resistance
| During charging of a capacitor of C = 100 μf through a resistance of 1 kΩ applied with 100 V, the voltage at time constant is ______.
A. 63.7 V
B. 36.7 V
C. 63.2 V
D. 100 V
Please scroll down to see the correct answer and solution guide.
Right Answer is: C
SOLUTION
The voltage is given by, \(V = {V_0}\left( {1 - {e^{ - \frac{t}{\tau }}}} \right)\)
Time constant = τ = RC = 100 μF × 1 kΩ = 0.1 sec
Given that t = τ = 0.1
\(V = 100\left( {1 - {e^{\frac{{0.1}}{{0.1}}}}} \right) = 63.2\;V\)