For a material with poisons ratio 0.25, the ratio of modulus of r
| For a material with poisons ratio 0.25, the ratio of modulus of rigidity to modulus of elasticity will be
A. 0.4
B. 1.2
C. 2.0
D. 3.6
Please scroll down to see the correct answer and solution guide.
Right Answer is: A
SOLUTION
Concept:
E = 2G(1 + v)
where E = Modulus of elasticity, G = Modulus of rigidity, ν = Poisons ratio.
Calculation:
Given:
Poisson's ratio, v = 0.25
the ratio of modulus of rigidity to modulus of elasticity = \(\frac{G}{E}\)
\(\frac{G}{E} = \frac{1}{{2\left( {1 + v} \right)}}\)
\(\frac{G}{E} = \frac{1}{{2\left( {1 + 0.25} \right)}}\)
\(\frac{G}{E} = 0.4\)
Hence the required value of the ratio of modulus of rigidity to modulus of elasticity is 0.4.