If |r - 6| = 11 and |2q - 12| = 8, what is the minimum possible v

| If |r - 6| = 11 and |2q - 12| = 8, what is the minimum possible value of q/r?

A. <span class="math-tex">\(- \frac{2}{5}\)</span>

B. -2

C. <span class="math-tex">\(\frac{{10}}{{17}}\)</span>

D. None of these

Please scroll down to see the correct answer and solution guide.

Explanation:

|r - 6| = 11

⇒ r – 6 = 11

∴ r = 17

Or – (r - 6) = 11

∴ r = - 5

Now,

|2q - 12| = 8

⇒ 2q – 12 = 8

∴ q = 10

Or 2q – 12 = - 8

∴ q = 2

Hence, minimum value of \(\left( {\frac{q}{r}} \right) = \left( {\frac{{10}}{{ - 5}}} \right) = - 2\)

Other combination of values of q and r will give value greater than -2.