In figure AB is a diameter of a circle with centre O an
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In figure AB is a diameter of a circle with centre O and AT is a tangent. If ∠AOQ=58∘, find ∠ATQ.
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Right Answer is:
SOLUTION
∠ABQ=12∠AOQ
⇒ 12×58=29
∠ A =90(AT is a tangent)
∠ BAT+ ∠ ABT + ∠ ATQ = 180 (angle sum property of triangle)
90 +29 + ∠ ATQ = 180∘
∠ ATQ = 180 - 119
∠ ATQ = 61∘
