In following figure O is the centre of the circle and AB is the d
| In following figure O is the centre of the circle and AB is the diameter. If ∠DAO=620 and ∠AOE= 1460 then, find the value of ∠EBC?
A. 1050
B. 1070
C. 1150
D. 1000
Please scroll down to see the correct answer and solution guide.
Right Answer is: B
SOLUTION
∠AOE = 1460
And ∠DAO = 620
Now, ∠AOE+∠EOB = 1800
∠EOB = 1800 - 1460
∠EOB = 340
Now, OB = OE (radius)
∠OBE = ∠OEB = x
Now in triangle OEB;
∠EOB+∠OBE + ∠OEB = 1800
340 + x + x = 1800
2x = 1460
x = 730
Now, ∠OBE + ∠EBC = 1800
730 + ∠EBC = 1800
∠EBC = 1070
