In the equation ax+by+c=0 if y=cx+db then x= d+ca+c −d−

In the equation $a x + b y + c = 0$ , if $y = \frac{(c x + d)}{b}$ then $x =$

$\frac{d + c}{a + c}$

$\frac{- d - c}{a + c}$

$\frac{a + c}{d + c}$

$\frac{b + c}{d + c}$

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Given $a x + b y + c = 0$ ,

Also given $y = \frac{(c x + d)}{b}$ ,

substitute this in $a x + b y + c = 0$

$\Rightarrow a x + [b \frac{(c x + d)}{b}] + c = 0$

$\Rightarrow a x + c x + d + c = 0$

$\Rightarrow (a + c) x = - d - c$

$∴ x = \frac{- d - c}{a + c}$