Question 4What is the area in sq units of the largest t

SOLUTION

Let ABCD be the rectangle of length l and width w.
Now, we construct a triangle of maximum area inside it in all possible ways.
$\because$ We know that,
Area of triangle $=\frac{1}{2}\times Base\times Height$
So, for maximum area, base and height of maximum length is needed.
Here, maximum base length = l
and maximum height = w
$\therefore$ Area (maximum) of triangle $=\frac{1}{2}\times l\times w=\frac{l\times w}{2}squnits$