tan9∘−tan27∘−tan63∘+tan81∘= 1 2 3 4 tan9∘−tan27∘−tan63∘

t a n 9^{\circ} - t a n 27^{\circ} - t a n 63^{\circ} + t a n 81^{\circ} =

A. 1

B. 2

C. 3

D. 4

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Right Answer is: D

SOLUTION

$t a n 9^{\circ} - t a n 27^{\circ} - t a n 63^{\circ} + t a n 81^{\circ} = t a n 9^{\circ} + c o t 9^{\circ} - (t a n 27^{\circ} + cot 27^{\circ}) = \frac{1}{s i n 9^{\circ} . c o s 9^{\circ}} - \frac{1}{s i n 27^{\circ} c o s 27^{\circ}} = \frac{2 [s i n 54^{\circ} - s i n 18^{\circ}]}{s i n 18^{\circ} . s i n 54^{\circ}} = 4$

tan9∘−tan27∘−tan63∘+tan81∘= 1 2 3 4 tan9∘−tan27∘−tan63∘

Right Answer is: D

SOLUTION

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