The force required to just move a body up an inclined p

| The force required to just move a body up an inclined plane is double the force required to just prevent it from sliding down. If

θ

is the angle of friction and

ϕ

is the angle which the plane makes with horizontal, then:

A. $t a n ϕ = 2 t a n θ$

B. $t a n ϕ = 3 t a n θ$

C. $t a n ϕ = t a n θ$

D. $t a n θ = 3 t a n ϕ$

Please scroll down to see the correct answer and solution guide.

Right Answer is: B

SOLUTION

Force required to just move up the body = $F_{u p} = m g s i n ϕ + μ m g c o s ϕ$ similarly
$F_{d o w n} = m g s i n ϕ - μ m g c o s ϕ F_{u p} = 2 F_{d o w n} m g s i n ϕ + μ m g c o s ϕ = 2 (m g s i n ϕ - μ m g c o s ϕ) t a n ϕ = 3 μ$
As we known $μ = t a n θ$
$∴ t a n ϕ = 3 t a n θ$

The force required to just move a body up an inclined p

Right Answer is: B

SOLUTION

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