The ratio of the height of a Porter governor (when the length of
The ratio of the height of a Porter governor (when the length of arms and links are equal) to the height of a Watt’s governor is
where m = Mass of the ball, and M = Mass of the load on the sleeve.
A. <span class="math-tex">\(\frac{m}{{m + M}}\)</span>
B. <span class="math-tex">\(\frac{M}{{m + M}}\)</span>
C. <span class="math-tex">\(\frac{{m + M}}{M}\)</span>
D. <span class="math-tex">\(\frac{{m + M}}{m}\)</span>
Please scroll down to see the correct answer and solution guide.
Right Answer is: D
SOLUTION
Concept:
The Porter governor is a modification of a Watt’s governor, with a central load attached to the sleeve.
For porter governor (When the length of arms is equal to the length of links):
\({N^2} = \frac{{m + M}}{m} \times \frac{{895}}{h}\;\)
For Watt Governor:
\({N^2} = \frac{{895}}{h}\)
The ratio of the height of a Porter governor (when the length of arms and links are equal) to the height of a Watt’s governor is \(\frac{{m + M}}{m}\)