The remainder obtained when 6y5+30y4+18y3+6y2+15y+3 is
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The remainder obtained when 6y5+30y4+18y3+6y2+15y+3 is divided by 2y3+1 is 3y2−6.
A.
True
B.
False
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Right Answer is: A
SOLUTION
Hence the remainder obtained is 3y2−6.