The RMS value of a sinusoidally varying waveform is 5√2. If it is
| The RMS value of a sinusoidally varying waveform is 5√2. If it is oscillating with a frequency of 50 Hz, the waveform can be represented as
A. 5√2 sin 50 πt
B. 10 sin 50 πt
C. 5√2 sin 100 πt
D. 10 sin 100 πt
Please scroll down to see the correct answer and solution guide.
Right Answer is: D
SOLUTION
Concept:
A general AC sinusoidal wave is expressed as:
v(t) = Vm sin (ωt)
Vm = Peak Value
ω = Angular frequency
RMS value 'or' the effective value of an alternating quantity is calculated as:
\({V_{rms}} = \sqrt{\frac{1}{T}\mathop \smallint \limits_0^T {v^2}\left( t \right)dt} \)
T = Time period
Calculation:
Given Vrms = 5√2
For a sinusoidally varying waveform, the RMS value is given by:
\(V_{rms}=\frac{V_m}{√2}\)
Vm = √2 × Vrms
Vm = √2 × 5√2 = 10
The waveform will be represented as:
V = Vm sin 2 πft
V =10 sin 2.π.50t
V = 10 sin 100 πt