The stress strain behavior of a material is shown in figure. Its
The stress strain behavior of a material is shown in figure. Its resilience and toughness, in Nm/m3 are respectively
A. 28 × 10<sup>4</sup>, 76 × 10<sup>4</sup>
B. 28 × 10<sup>4</sup>, 48 × 10<sup>4</sup>
C. 14 × 10<sup>4</sup>, 90 × 10<sup>4</sup>
D. 76 × 10<sup>4</sup>, 28 × 10<sup>4</sup>
Please scroll down to see the correct answer and solution guide.
Right Answer is: C
SOLUTION
Concept:
Modulus of resilience:
Resilience per unit volume is known as the modulus of resilience which is the area under the stress-strain curve up to the elastic limit.
Modulus of toughness:
Toughness per unit volume is known as the modulus of toughness which is the total area under the stress-strain curve.
Calculation:
Given:
\({U_{res}} = \frac{1}{2}{\sigma _e}\epsilon = \frac{1}{2} \times 70 \times {10^6} \times 0.004 = 14 \times {10^4}\;Nm/{m^3}\)
\({U_{tough}} = \) The total area under the stress-strain diagram.
\( = \left[ {\frac{1}{2} \times 70 \times 0.004 + \frac{1}{2} \times \left( {120 - 70} \right)\left( {0.012 - 0.004} \right) + 70\left( {0.012 - 0.004} \right)} \right] \times {10^6}\)
\(= \left[ {\frac{1}{2} \times 70 \times 0.004 + \frac{1}{2} \times 50 \times 0.008 + 70 \times 0.008} \right] \times {10^6} = 90 \times {10^4}\;Nm/{m^3}\)
Proof resilience
- It is defined as the maximum strain energy stored in a body.
- So, it is the quantity of strain energy stored in a body when strained up to the elastic limit (ability to store or absorb energy without permanent deformation).
Modulus of resilience
- It is defined as proof resilience per unit volume.
- It is the area under the stress-strain curve up to the elastic limit.
Modulus of toughness
- It is the ability to absorb energy up to fracture.
- From the stress-strain diagram, the area under the complete curve gives the measure of modules of toughness.