Two parallel glass plates are dipped partly in the liqu

Two parallel glass plates are dipped partly in the liquid of density 'd' keeping them vertical. If the distance between the plates is 'x', surface tension for liquids is T and angle of contact is θ , then rise of liquid between the plates due to capillary will be

$\frac{T c o s θ}{x d}$

$\frac{2 T c o s θ}{x d g}$

$\frac{2 T}{x d g c o s θ}$

$\frac{T c o s θ}{x d g}$

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Right Answer is: B

SOLUTION

Let the width of each plate is b and due to surface tension liquid will rise upto height h then upward force due to surface tension = $2 T b c o s θ$

Weight of the liquid rises in between the plates = $V d g = (b x h) d g$

Equating (i) and (ii) we get, $2 T c o s θ = b x h d g$

$∴ h = \frac{2 T c o s θ}{x d g}$

Two parallel glass plates are dipped partly in the liqu

Right Answer is: B

SOLUTION

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