Two pendula have time periods T and 5T4 They start SHM

| Two pendula have time periods T and

\frac{5 T}{4}

. They start SHM at the same time from the mean position. The phase difference between them after the pendulum with larger period completes one oscillation is

A. $\frac{π}{3}$

B. $\frac{π}{6}$

C. $\frac{π}{2}$

D. $π$

Please scroll down to see the correct answer and solution guide.

Right Answer is: C

SOLUTION

Since $\frac{5 T}{4} = T + \frac{T}{4}$ , the phase difference is $\frac{π}{2}$ .

Two pendula have time periods T and 5T4 They start SHM

Right Answer is: C

SOLUTION

Related QuestionsA simple pendulum of length 1 m is taken to height h hA particle is executing SHM After 2 seconds of crossinThe equation of motion of a body of mass 20 kg in SHM iA mass m is attached to a spring oscillate with a perio

Related Questions
A simple pendulum of length 1 m is taken to height h h
A particle is executing SHM After 2 seconds of crossin
The equation of motion of a body of mass 20 kg in SHM i
A mass m is attached to a spring oscillate with a perio