Two vectors →A=3^i+8^j−2^k and →B=6^i+16^j+x^k are suc
![Two vectors →A=3^i+8^j−2^k and →B=6^i+16^j+x^k are suc](/img/relate-questions.png)
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Two vectors →A=3^i+8^j−2^k and →B=6^i+16^j+x^k are such that the component of →B perpendicular to →A is zero. Then the value of x will be:
A.
-8
B.
+4
C.
-4
D.
8
Please scroll down to see the correct answer and solution guide.
Right Answer is: C
SOLUTION
Given→B||→A
⇒→B=k→A
⇒6^i+16^j+x^k=k(3^i+8^j−2^k)
⇒k=2
⇒x=−4