Two vectors →A=3^i+8^j−2^k  and →B=6^i+16^j+x^k are suc

Two vectors →A=3^i+8^j−2^k  and →B=6^i+16^j+x^k are suc
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Two vectors A=3^i+8^j2^k  and B=6^i+16^j+x^k are such that the component of B perpendicular to A is zero. Then the value of x will be:
 

A.

-8

B.

+4

C.

-4

D.

8

Please scroll down to see the correct answer and solution guide.

Right Answer is: C

SOLUTION

GivenB||A

B=kA

6^i+16^j+x^k=k(3^i+8^j2^k)

k=2

x=4