What is the highest number which when divides the numbers 1026, 2
| What is the highest number which when divides the numbers 1026, 2052 and 4102, leaving remainders 2, 4 and 6 respectively?
A. 512
B. 1024
C. 128
D. 256
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Right Answer is: B
SOLUTION
The highest number which when divides the numbers 1026, 2052 and 4102, leaving remainders 2, 4 and 6 respectively, then
⇒ 1026 - 2 = 1024
⇒ 2052 - 4 = 2048
⇒ 4102 - 6 = 4096
HCF of 1024, 2048 and 4096 is 1024
