What will be the thermal stress (in MPa) developed in a rod havin

What will be the thermal stress (in MPa) developed in a rod havin
| What will be the thermal stress (in MPa) developed in a rod having a diameter of 4 cm and length of 2 m. It experiences heating from temperature 50°C to 200°C. The coefficient of thermal expansion is α = 10 × 10-6/°C and young’s modulus is 250 GPa?

A. 300

B. 325

C. 350

D. 375

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Right Answer is: D

SOLUTION

Thermal stresses are the stresses induced in a body due to change in temperature.

\({\sigma _t} = E\alpha {\rm{\Delta }}T = 250 \times {10^3} \times 10 \times {10^{ - 6}} \times 150 = 375\;MPa\)

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