A ball bearing is subjected to a radial load of 2500 N and an axi

A ball bearing is subjected to a radial load of 2500 N and an axi
| A ball bearing is subjected to a radial load of 2500 N and an axial force of 1000 N. The catalogue gives the following data: Radial factor = 0.4, Axial thrust factor = 1.5, Static load rating = 10000 N, Dynamic load Rating = 7500 N. The bearing life in millions of revolutions is

A. 1

B. 9

C. 27

D. 8

Please scroll down to see the correct answer and solution guide.

Right Answer is: C

SOLUTION

Explanation:

Given:

Fr = 2500 N, Fa = 1000 N, X = 0.4, Y = 1.5, S = 10000 N

Now, the equivalent load on bearing is given by:

Pe = XFr + YFa

Pe = 0.4 × 2500 + 1.5 × 1000 = 2500 N

So,

\({L_{90}} = {\left( {\frac{C}{{{P_e}}}} \right)^3} \equiv {\left( {\frac{{7500}}{{2500}}} \right)^3}{\rm{million\;revolutions}}.\)

∴ L90 = 33 = 27 million revolutions

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