A force of 100 N is applied on a block of mass 3kg as s

A force of 100 N is applied on a block of mass 3kg as shown below. The coefficient of friction between wall and the block is $\frac{1}{4}$ . The friction force acting on the block is

20 N upwards

20 N downwards

25 N upwards

15 N downwards

Please scroll down to see the correct answer and solution guide.

Right Answer is: B

SOLUTION

$f_{m a x} = μ N = (\frac{1}{4}) (\frac{100 \sqrt{3}}{2})$

$= \frac{25 \sqrt{3}}{2}$ Newton

Since net force (excluding friction) acting on the block is 20 N upwards therefore f=20N downwards.

A force of 100 N is applied on a block of mass 3kg as s

Right Answer is: B

SOLUTION

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